Datetime 基于开始日期和日期查询设置“我的到/从日期”

首先，感谢大家昨天的帮助

我已经设法让我的报告工作（到目前为止），所以现在我需要在标题中显示日期周期（从：到：）。以下是查询：

Declare @startdate  datetime
Declare @enddate  datetime
Declare @BeginningDate datetime

set @BeginningDate = '12-01-2011'

IF Month(@BeginningDate) < (Month(GETDATE())-1)--(YTD)
BEGIN
set @startdate = DATEADD(yy, DATEDIFF(yy,0,getdate()), 0)
set @enddate = dateadd(day, datediff(day, 0, getdate()), 0)
END

IF Month(@BeginningDate) = (Month(GETDATE())-1)--(MTD)
BEGIN
set @startdate = dateadd  (mm,-1,
  DATEADD(dd,-(DAY(DATEADD(mm,1,convert(varchar(10),getdate(),111)))-1),
  DATEADD(mm,0,convert(varchar(10),getdate(),111))))--BEGINNING OF PRIOR MONTH
set @enddate =DATEADD(dd,-1,
  DATEADD(mm, 
  DATEDIFF(m,0,convert(varchar(10),getdate(),111)),0))--END OF PRIOR MONTH
END


IF Month(@BeginningDate) = (Month(GETDATE()))--(Current Period)
BEGIN
set @startdate = dateadd(month, datediff(month, 0, 
  dateadd(day, datediff(day, 1, getdate()), 0)), 0)--BEGINNING OF CURRENT MONTH
set @enddate = dateadd(day, 
  datediff(day, 0, getdate()), 0)--THROUGH CURRENT MONTH (TODAY)
END

如果用户选择的开始日期大于上月（例如10/1），则返回的日期应为

1/1/2011

至

12/16/2011

我希望这能澄清问题

---

谢谢

我之前发布过这篇文章，您需要使用一个数据集来调用日期函数。看看你是否能做到这一点：它能创造奇迹。具体看一下Reporting Services人员的

部分

对于您来说，这将非常简单，如果他们选择2011年11月27日，您希望返回2011年11月1日，您只需调用数据集，该数据集反过来调用函数month_start。所有这些都在该线程中有很好的文档记录，并被广泛使用

它的jist是您在RS中需要此功能：

CREATE FUNCTION [dbo].[udfCommonDates] (@date datetime)
RETURNS @t table (week_start datetime,
                  week_end datetime,
                  lastweek_start datetime,
                  lastweek_end datetime,
                  month_start datetime,
                  month_end datetime,
                  lastmonth_start datetime,
                  lastmonth_end datetime,
                  yesterday_start datetime,
                  yesterday_end datetime,
                  today_start datetime,
                  today_end datetime,
                  thisweek_monday_start datetime,
                  thisweek_monday_end datetime,
                  year_start datetime,
                  year_end datetime,
                  tomorrow_noon datetime,
                  today_noon datetime,
                  date_only datetime)
BEGIN
   INSERT @t
   SELECT
   dbo.get_week_start ( @date ) AS week_start,
   dbo.get_week_end   ( @date ) AS week_end,
   dbo.get_week_start ( DATEADD(d, -7, @date ) ) AS lastweek_start,
   dbo.get_week_end   ( DATEADD(d, -7, @date ) ) AS lastweek_end,
   dbo.get_month_start( @date ) AS month_start,
   dbo.get_month_end  ( @date ) AS month_end,
   dbo.get_month_start ( DATEADD(m,-1, @date) ) AS lastmonth_start,
   dbo.get_month_end  ( DATEADD(m,-1,@date) ) AS lastmonth_end,
   dbo.get_yesterday_start ( @date ) AS yesterday_start,
   dbo.get_yesterday_end ( @date ) AS yesterday_end,
   dbo.get_today_start (@date) AS today_start,
   dbo.get_today_end ( @date ) AS today_end,
   dbo.get_weekday_start(1,@date) AS thisweek_monday_start,
   dbo.get_weekday_end(1,@date) AS thisweek_monday_end,
   dbo.get_year_start(@date) AS year_start,
   dbo.get_year_end(@date) AS year_end,  
   dbo.get_tomorrow_noon(@date) AS TomorrowNoon,
   dbo.get_today_noon(@date) AS TodayNoon,
   dbo.get_date_only(@date) AS DateOnly
RETURN
END

然后，您需要为每个函数使用标量值函数：

   CREATE FUNCTION [dbo].[get_date_only] (@date datetime)
    RETURNS datetime
    WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
    AS    
    BEGIN
        RETURN dateadd(day, DateDiff(day, 0, GetDate()), 0)
    END
    GO

CREATE FUNCTION [dbo].[get_month_end] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    
BEGIN
   RETURN dateadd(ms, -3, dateadd (m,datediff(m,0,
          dateadd(m,1,@date)),0))
END
GO

CREATE FUNCTION [dbo].[get_month_start] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    
BEGIN
   RETURN dateadd(m,datediff(m,0, @date),0)
   END
GO

CREATE FUNCTION [dbo].[get_today_end] (@today datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    
BEGIN
   return dateadd(ms, -3, datediff(d,0,dateadd(d,1,@today)))
END
GO

CREATE FUNCTION [dbo].[get_today_noon](@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   RETURN DATEADD(hh, 12, DATEADD(d,DATEDIFF(d,0, @date),0))
END
GO

CREATE FUNCTION [dbo].[get_today_start] (@today datetime)
RETURNS datetime 
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   return dateadd(day, 0, datediff(d,0,@today))
END
GO

CREATE FUNCTION [dbo].[get_tomorrow_noon](@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   RETURN DATEADD(hh, 12, DATEADD(d,DATEDIFF(d,-1, @date),0))
END
GO

CREATE FUNCTION [dbo].[get_week_end] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   return dateadd(yyyy, datepart(yyyy,
      dateadd(weekday,7-datepart(weekday, @date),@date))-1900, 0)
    + dateadd(ms, -3,
      dateadd(dy, datepart(dy,
     dateadd(weekday,7-datepart(weekday, @date),@date)),0) )
END
GO

CREATE FUNCTION [dbo].[get_week_start] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   return dateadd(yyyy, datepart(yyyy,
      dateadd(weekday,1-datepart(weekday, @date),@date))-1900, 0)
    + dateadd(dy, datepart(dy,
      dateadd(weekday,1-datepart(weekday, @date),@date))-1,0)
END
GO

CREATE FUNCTION [dbo].[get_weekday_end] (@weekday tinyint,
                                 @date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   return dateadd(yyyy, datepart(yyyy,
      dateadd(weekday,@weekday-
      datepart(weekday, @date),@date))-1900, 0)
    + dateadd(ms, -3,
      dateadd(dy, datepart(dy,
      dateadd(weekday,@weekday-datepart(weekday, @date),
                                        @date)),0) )
END
GO

CREATE FUNCTION [dbo].[get_weekday_start] (@weekday tinyint,
                                   @date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   return dateadd(yyyy, datepart(yyyy,
      dateadd(weekday,@weekday-
      datepart(weekday, @date),@date))-1900, 0)
    + dateadd(dy, datepart(dy,
      dateadd(weekday,@weekday-datepart(weekday, @date),
                                        @date))-1,0)
END
GO

CREATE FUNCTION [dbo].[get_year_end] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
RETURN DATEADD(year, DATEDIFF(year, 0, GetDate())+1, 0)-1
END
GO

CREATE FUNCTION [dbo].[get_year_start] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   RETURN DATEADD(year,DATEDIFF(year,0, @date),0)
END
GO

CREATE FUNCTION [dbo].[get_yesterday_end] (@today datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   return dateadd(ms, -3, datediff(d,0,@today))
END
GO

CREATE FUNCTION [dbo].[get_yesterday_start] (@today datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   RETURN dateadd(day, -1, datediff(d,0,@today))
END
GO

现在，reporting services的工作已经完成，请记住数据集可以是存储过程或直接表。因此，您只需创建一个存储过程：

CREATE PROCEDURE [dbo].[uspCommonDates] AS
begin
   set datefirst 1
   declare @date datetime
   set @date = getdate()
   select * from dbo.udfCommonDates(@date)
end

并将此存储过程用作
数据集
。现在您可以访问所有这些漂亮的日期函数了。现在，您可以转到参数部分，像这样调用这些函数：

@Ken White。你是如何让约会变得“高雅”的？您是否像处理代码一样缩进？还在努力学习这里的所有交易技巧，以尽量减少被炒鱿鱼：D谢谢！反勾号（反撇号，与美国键盘上的~在同一个键上，就在
Esc
）周围，将其视为内联代码。谢谢！当我在前面的一个问题上注意到这一点时，我忘了问这个问题。@AaronSmith-如果你这样处理的话，
iif
的情况会变得非常糟糕。它将不断增长，一旦您认为它能够工作，需求就会改变。你需要使用一些常用的日期函数，如果你有一个日期，你可以将它传递给一个函数，它可以向你返回一些很好的信息，比如一个月的第一天，一个月的最后一天，一个月的名称，日期过去的前一周，等等。请看下面我的答案。@john我想问你如何将iif与下面你的建议结合起来。我的问题是因为我使用此日期问题的数据集。From/To将根据
@BeginningDate
的不同而有所不同，因此我不确定如何将您的建议（顺便说一句，这是惊人的）与我的报告要求结合起来。
CREATE PROCEDURE [dbo].[uspCommonDates] AS
begin
   set datefirst 1
   declare @date datetime
   set @date = getdate()
   select * from dbo.udfCommonDates(@date)
end