Db2存储过程错误（在使用它的上下文中无效）

我的问题是，当我调用存储过程时，它不工作

drop procedure DELETE_WITH_COMMIT_COUNT1
DB20000I  The SQL command completed successfully.

CREATE PROCEDURE DELETE_WITH_COMMIT_COUNT1(IN v_TABLE_NAME VARCHAR(24), IN v_COMMIT_COUNT INTEGER )
    NOT DETERMINISTIC
    LANGUAGE SQL
P1 : BEGIN

    -- DECLARE Statements
    DECLARE SQLCODE INTEGER;
    DECLARE v_DELETE_QUERY VARCHAR(1024);
    DECLARE v_DELETE_STATEMENT STATEMENT;

P2 : BEGIN
    DECLARE V1 CHAR(24) FOR BIT DATA;
    DECLARE V2 CHAR(24) FOR BIT DATA ;

DECLARE cur1 CURSOR WITH RETURN TO CLIENT FOR select min(MESSAGE_ID),max(MESSAGE_ID) from TESTING where TIMESTAMP between (select TIMESTAMP(date(min(timestamp))) from TESTING with ur) and (select TIMESTAMP(date(min(timestamp))) + 1 day from TESTING with ur) ;

OPEN cur1;
FETCH FROM cur1 INTO V1, V2;

   SET v_DELETE_QUERY = 'DELETE FROM (SELECT 1 FROM ' || v_TABLE_NAME || ' WHERE MESSAGE_ID between V1 and V2 '
        || ' FETCH FIRST ' || RTRIM(CHAR(v_COMMIT_COUNT)) || ' ROWS ONLY) AS DELETE_TABLE';

    PREPARE v_DELETE_STATEMENT FROM v_DELETE_QUERY;

    DEL_LOOP:
        LOOP
            EXECUTE v_DELETE_STATEMENT;
            IF SQLCODE = 100 THEN
                LEAVE DEL_LOOP;
            END IF;
            COMMIT;
        END LOOP;

    COMMIT;
  END P2;
END P1
DB20000I  The SQL command completed successfully.

我的过程已成功创建，但调用它时出现以下问题：

db2调用DELETE_和_COMMIT_COUNT1“TESTING”，50 SQL0206N V1为 在使用它的上下文中无效。SQLSTATE=42703

更多信息：

db2从测试中选择minMESSAGE\u ID和maxMESSAGE\u ID 从测试中选择TIMESTAMPdatemintimestamp之间的时间戳 使用ur并从中选择TIMESTAMPdatemintimestamp+1天 使用ur进行测试

我想删除这些值之间的记录，目前我有99条最小和最大消息id之间的记录

message_id column is defined as CHAR(24) FOR BIT DATA on the table .

---

你的问题在于这句话：

SET v_DELETE_QUERY = 'DELETE FROM (SELECT 1 FROM ' || v_TABLE_NAME || ' WHERE   MESSAGE_ID between V1 and V2 '
        || ' FETCH FIRST ' || RTRIM(CHAR(v_COMMIT_COUNT)) || ' ROWS ONLY) AS DELETE_TABLE';

在该语句中，您似乎希望使用先前声明的变量V1和V2的值：

' WHERE   MESSAGE_ID between V1 and V2 '

DB2将其视为字符串文本。相反，请尝试更改语句的这一部分，如下所示：

SET v_DELETE_QUERY = 'DELETE FROM (SELECT 1 FROM ' || v_TABLE_NAME || ' WHERE   MESSAGE_ID between ' || V1 || ' and ' || V2
            || ' FETCH FIRST ' || RTRIM(CHAR(v_COMMIT_COUNT)) || ' ROWS ONLY) AS DELETE_TABLE';

---

您的问题在这里：“| |”消息_ID在V1和V2之间的位置”`

SET v_DELETE_QUERY = 'DELETE FROM (SELECT 1 FROM ' || v_TABLE_NAME || ' WHERE   MESSAGE_ID between ' || V1 || ' and ' || V2
            || ' FETCH FIRST ' || RTRIM(CHAR(v_COMMIT_COUNT)) || ' ROWS ONLY) AS DELETE_TABLE';