Dictionary 通过对相同键的值求和在Julia中添加字典
我在茱莉亚有两本字典Dictionary 通过对相同键的值求和在Julia中添加字典,dictionary,counter,julia,Dictionary,Counter,Julia,我在茱莉亚有两本字典a1和a2 a1 = {"A"=>1, "B"=>2} a2 = {"A"=>4, "B"=>1, "C"=>3} 我想把它结合起来得到这个 final={"A"=>5, "B"=>3, "C"=>3} 在Python中,我将字典转换为集合计数器,并将它们组合在一起 查看DataStructures.jl计数器 julia> using DataStructures: counter julia> a1 = D
a1
和a2
a1 = {"A"=>1, "B"=>2}
a2 = {"A"=>4, "B"=>1, "C"=>3}
我想把它结合起来得到这个
final={"A"=>5, "B"=>3, "C"=>3}
在Python中,我将字典转换为集合计数器,并将它们组合在一起 查看DataStructures.jl计数器
julia> using DataStructures: counter
julia> a1 = Dict{ASCIIString, Int64}("A"=>1, "B"=>2)
Dict{ASCIIString,Int64} with 2 entries:
"B" => 2
"A" => 1
julia> a2 = Dict{ASCIIString, Int64}("A"=>4, "B"=>1, "C"=>3)
Dict{ASCIIString,Int64} with 3 entries:
"B" => 1
"A" => 4
"C" => 3
julia> merge(counter(a1), counter(a2)).map
Dict{ASCIIString,Int64} with 3 entries:
"B" => 3
"A" => 5
"C" => 3
对于现在看到这个的任何人来说,
计数器
不再是必需的——使用merge(+,a1,a2)
julia> a1 = Dict("A"=>1, "B"=>2)
Dict{String,Int64} with 2 entries:
"B" => 2
"A" => 1
julia> a2 = Dict("A"=>4, "B"=>1, "C"=>3)
Dict{String,Int64} with 3 entries:
"B" => 1
"A" => 4
"C" => 3
julia> merge(+, a1, a2)
Dict{String,Int64} with 3 entries:
"B" => 3
"A" => 5
"C" => 3