Django Rest框架返回空JSON

我只是通过以下几个教程开始实现Django Rest框架，但是我无法解决我的问题

实际上，我的API返回空JSON字符串：

这是我的代码：

从rest_框架导入序列化程序 从wall.models导入文章

序列化程序.py

class ArticlesSerializer(serializers.Serializer):
    class Meta:
        model = Articles
        fields = ('title',)

class ArticlesView(generics.ListAPIView):
    queryset = Articles.objects.all()
    serializer_class = ArticlesSerializer

url('articles/', ArticlesView.as_view(), name="api-articles"),

class Articles(models.Model):
    title = models.CharField(max_length=100, null=False, verbose_name="Titre")

视图.py

class ArticlesSerializer(serializers.Serializer):
    class Meta:
        model = Articles
        fields = ('title',)

class ArticlesView(generics.ListAPIView):
    queryset = Articles.objects.all()
    serializer_class = ArticlesSerializer

url('articles/', ArticlesView.as_view(), name="api-articles"),

class Articles(models.Model):
    title = models.CharField(max_length=100, null=False, verbose_name="Titre")

url.py

class ArticlesSerializer(serializers.Serializer):
    class Meta:
        model = Articles
        fields = ('title',)

class ArticlesView(generics.ListAPIView):
    queryset = Articles.objects.all()
    serializer_class = ArticlesSerializer

url('articles/', ArticlesView.as_view(), name="api-articles"),

class Articles(models.Model):
    title = models.CharField(max_length=100, null=False, verbose_name="Titre")

型号.py

class ArticlesSerializer(serializers.Serializer):
    class Meta:
        model = Articles
        fields = ('title',)

class ArticlesView(generics.ListAPIView):
    queryset = Articles.objects.all()
    serializer_class = ArticlesSerializer

url('articles/', ArticlesView.as_view(), name="api-articles"),

class Articles(models.Model):
    title = models.CharField(max_length=100, null=False, verbose_name="Titre")

---

我有很多文章，所以JSON返回的文章和我数据库中的文章一样多，但没有显示其他内容。为什么？

您应该从

序列化程序继承序列化程序。ModelSerializer

而不是

序列化程序。序列化程序

：

class ArticlesSerializer(serializers.ModelSerializer):
    class Meta:
        model = Articles
        fields = ('title',)