Django从ListView创建模型

我有一个ListView来列出模型的实例，我希望用户能够从同一页面创建一个新实例

我尝试了CreateView、FormMixin和ModelFormMixin的多重继承，我让它们都工作了，但是当表单无效时，我没有得到验证，我只得到了“视图”对象没有属性“object\u list”

我怎样才能做到这一点

为了处理模型创建，我是否应该分割关注点并有一个单独的视图？如果是这样，如何将无效错误返回到同一模板

我的自动取款机代码：

@method_decorator(login_required, name='dispatch')
class MyView(CreateView, ListView):

    model = MyModel
    form_class = MyModelForm
    template_name = 'MyPage.html'
    success_url = reverse_lazy('my_page')

编辑：添加回溯：

Request Method: POST
Request URL: http://127.0.0.1:8000/create/

Django Version: 3.0.8
Python Version: 3.8.2
Installed Applications:
['django.contrib.admin',
 'django.contrib.auth',
 'django.contrib.contenttypes',
 'django.contrib.sessions',
 'django.contrib.messages',
 'django.contrib.staticfiles',
 'tracker']
Installed Middleware:
['django.middleware.security.SecurityMiddleware',
 'django.contrib.sessions.middleware.SessionMiddleware',
 'django.middleware.common.CommonMiddleware',
 'django.middleware.csrf.CsrfViewMiddleware',
 'django.contrib.auth.middleware.AuthenticationMiddleware',
 'django.contrib.messages.middleware.MessageMiddleware',
 'django.middleware.clickjacking.XFrameOptionsMiddleware']



Traceback (most recent call last):
  File "/Users/bidu/gitfolder/expense_tracker/env/lib/python3.8/site-packages/django/core/handlers/exception.py", line 34, in inner
    response = get_response(request)
  File "/Users/bidu/gitfolder/expense_tracker/env/lib/python3.8/site-packages/django/core/handlers/base.py", line 115, in _get_response
    response = self.process_exception_by_middleware(e, request)
  File "/Users/bidu/gitfolder/expense_tracker/env/lib/python3.8/site-packages/django/core/handlers/base.py", line 113, in _get_response
    response = wrapped_callback(request, *callback_args, **callback_kwargs)
  File "/Users/bidu/gitfolder/expense_tracker/env/lib/python3.8/site-packages/django/views/generic/base.py", line 71, in view
    return self.dispatch(request, *args, **kwargs)
  File "/Users/bidu/gitfolder/expense_tracker/env/lib/python3.8/site-packages/django/utils/decorators.py", line 43, in _wrapper
    return bound_method(*args, **kwargs)
  File "/Users/bidu/gitfolder/expense_tracker/env/lib/python3.8/site-packages/django/contrib/auth/decorators.py", line 21, in _wrapped_view
    return view_func(request, *args, **kwargs)
  File "/Users/bidu/gitfolder/expense_tracker/env/lib/python3.8/site-packages/django/views/generic/base.py", line 97, in dispatch
    return handler(request, *args, **kwargs)
  File "/Users/bidu/gitfolder/expense_tracker/env/lib/python3.8/site-packages/django/views/generic/edit.py", line 172, in post
    return super().post(request, *args, **kwargs)
  File "/Users/bidu/gitfolder/expense_tracker/env/lib/python3.8/site-packages/django/views/generic/edit.py", line 144, in post
    return self.form_invalid(form)
  File "/Users/bidu/gitfolder/expense_tracker/env/lib/python3.8/site-packages/django/views/generic/edit.py", line 61, in form_invalid
    return self.render_to_response(self.get_context_data(form=form))
  File "/Users/bidu/gitfolder/expense_tracker/env/lib/python3.8/site-packages/django/views/generic/edit.py", line 67, in get_context_data
    return super().get_context_data(**kwargs)
  File "/Users/bidu/gitfolder/expense_tracker/env/lib/python3.8/site-packages/django/views/generic/detail.py", line 100, in get_context_data
    return super().get_context_data(**context)
  File "/Users/bidu/gitfolder/expense_tracker/env/lib/python3.8/site-packages/django/views/generic/list.py", line 115, in get_context_data
    queryset = object_list if object_list is not None else self.object_list

Exception Type: AttributeError at /create/
Exception Value: 'CreateTransactionView' object has no attribute 'object_list'

---

您可以按照以下步骤创建自定义表单验证：

class联系人表单（forms.Form）：
#一切照旧
def清洁_收件人（自身）：
数据=自清理的_数据['recipients']
如果“fred@example.com“不在数据中：
raise forms.ValidationError（“您忘记了Fred！”）
返回数据

“视图”对象没有“对象列表”属性

---

但是，关于您遇到的这个错误，在做了一些研究之后，我认为您需要重写默认的

self.object\u list

变量，如中所述。但是，我想在您开始使用CreateView之后，您不必再处理这个问题。

很多视图都涉及表单和对象列表。与其尝试混入内容，不如将queryset添加到上下文数据中，如下所示。不要错过删除类

ListView

@方法\u装饰器（需要登录，name='dispatch'） 类MyView（CreateView）： model=MyModel form_class=MyModelForm 模板名称='MyPage.html' success\u url=reverse\u lazy（“我的页面”） def获取上下文数据（自身，**kwargs）： kwargs['object_list']=self.model.objects.all（） 返回super（MyView，self）。获取上下文数据（**kwargs）

---

为什么不在

ListView

页面上创建一个链接，链接到

CreateView

页面？你能发布回溯吗？在POST请求中，您可能需要添加一些设置

object\u list

的方法，但这两个类的常见方法是

get\u context\u object\u name

things@MeL如果表单验证无效，我需要能够在同一模板中获得表单验证，如果我分离视图，我不知道如何进行此操作。@IainShelvington添加了回溯使用此示例，我得到了错误

“MyView”对象没有属性“object\u list”

。如果我将

类MyView（CreateView，ListView）：

更改为

类MyView（ListView，CreateView）：

我在GET请求中遇到以下错误：

“MyView”对象没有属性“object”

@method_decorator(login_required, name='dispatch') class MyView(CreateView): model = MyModel form_class = MyModelForm template_name = 'MyPage.html' success_url = reverse_lazy('my_page') def get_context_data(self, **kwargs): kwargs['object_list'] = self.model.objects.all() return super(MyView, self).get_context_data(**kwargs)