Django-提交链接

我有一个带有POST提交按钮的表单。我想在提交表单以及表单.u有效（）时链接到新页面

在视图中还是在模板中创建链接更好？怎么做

view.py：

from django.shortcuts import render_to_response
from ezmapping.models import *
from django.forms.models import modelformset_factory

def setName(request):
    ezAppFormSet = modelformset_factory(ezApp, extra=1, fields=('name'))
    formset = ezAppFormSet(queryset=ezApp.objects.none())
    if request.method == 'POST':
        formset = ezAppFormSet(request.POST, request.FILES)
        if formset.is_valid():
            formset.save()
    return render_to_response("project/manage_new.html", {'formset': formset, 'title': "New"}, context_instance=RequestContext(request))

template.html

 {% extends "basemap.html" %}
 {% block content %}
 <table border="1">
   <tr>
   <td>
    <h1>Define new App options</h1>
    {% if formset.errors %}
        <p style="color: red;">
            Please correct the error{{ formset.errors|pluralize }} below.
        </p>
    {% endif %}
    <form method="post" action="." encrypt="multipart/form-data">{% csrf_token %}
            {{ formset.as_p }}
        <input type="submit" value="Submit">
    </form>
</td>
</tr>
</table>
{% endblock %}

{%extends“basemap.html”%}
{%block content%}
定义新的应用程序选项
{%if formset.errors%}

请更正下面的错误{formset.errors | pluralize}}。

{%endif%}
{%csrf_令牌%}
{{formset.as_p}}
{%endblock%}

当然可以。只需在您的条件for

request.method==“POST”

中返回一个render\u to\u响应，或者可以选择将上下文和模板设置为变量，以将其交给render\u to\u响应：

意译：

def foo(request):
    template = 'template1.html'
    # form and formsets here set into `context` as a dictionary

    if request.method == 'POST':
        template = 'template2.html'

    return render_to_response(template, context)

[编辑]

---

当我重新阅读您的问题时，如果您希望在表单有效的情况下重定向到其他视图，请返回一个HttpResponseRedirect。

如果我正确理解您的问题

你的看法：

from django.shortcuts import render_to_response
from ezmapping.models import *
from django.forms.models import modelformset_factory

def setName(request):
    ezAppFormSet = modelformset_factory(ezApp, extra=1, fields=('name'))
    formset = ezAppFormSet(queryset=ezApp.objects.none())
    if request.method == 'POST':
        formset = ezAppFormSet(request.POST, request.FILES)
        if formset.is_valid():
            formset.save()
            submit_link = True # 2*
        else:
            submit_link = False
    return render_to_response("project/manage_new.html", {'submit_link': submit_link, 'formset': formset, 'title': "New"}, context_instance=RequestContext(request))

您的模板：

{% extends "basemap.html" %}
 {% block content %}
 <table border="1">
   <tr>
   <td>
    <h1>Define new App options</h1>
    {% if formset.errors %}
        <p style="color: red;">
            Please correct the error{{ formset.errors|pluralize }} below.
        </p>
    {% endif %}
    <form method="post" action="." encrypt="multipart/form-data">{% csrf_token %}
            {{ formset.as_p }}
        <input type="submit" value="Submit">
    </form>

    {% if submit_link %} 
      <a href='/next/'>Data is saved, let's continue.</a>
    {% endif %}
</td>
</tr>
</table>
{% endblock %}

---

您可以在视图中使用HttpResponseRedirect（）而不是2*

，如下所示：

from django.shortcuts import render_to_response
from ezmapping.models import *
from django.forms.models import modelformset_factory

def setName(request):
    ezAppFormSet = modelformset_factory(ezApp, extra=1, fields=('name'))
    formset = ezAppFormSet(queryset=ezApp.objects.none())
    if request.method == 'POST':
        formset = ezAppFormSet(request.POST, request.FILES)
        if formset.is_valid():
            formset.save()
            next_link = u"/next/"
            return HttpResponseRedirect(next_link)

    return render_to_response("project/manage_new.html", {'formset': formset, 'title': "New"}, context_instance=RequestContext(request))

---

“当form.u是有效的（）时”是什么意思？是否要验证此必需页面上的表单，还是希望该页面在成功验证前一页后获得重定向？

from django.shortcuts import render_to_response
from ezmapping.models import *
from django.forms.models import modelformset_factory

def setName(request):
    ezAppFormSet = modelformset_factory(ezApp, extra=1, fields=('name'))
    formset = ezAppFormSet(queryset=ezApp.objects.none())
    if request.method == 'POST':
        formset = ezAppFormSet(request.POST, request.FILES)
        if formset.is_valid():
            formset.save()
            next_link = u"/next/"
            return HttpResponseRedirect(next_link)

    return render_to_response("project/manage_new.html", {'formset': formset, 'title': "New"}, context_instance=RequestContext(request))