Django 自定义管理员创建表单
因此,在我的模型中,我有一个特定的配置文件,它与一个更一般的配置文件有一对一的关系,它与django用户模型有一对一的关系。我希望能够在django管理中填写一个表单,并创建所有三个模型的实例,并且已经建立了关系 我没有太多地与django管理员打交道,所以我不完全确定如何让它工作。以下是我失败的尝试:Django 自定义管理员创建表单,django,django-admin,Django,Django Admin,因此,在我的模型中,我有一个特定的配置文件,它与一个更一般的配置文件有一对一的关系,它与django用户模型有一对一的关系。我希望能够在django管理中填写一个表单,并创建所有三个模型的实例,并且已经建立了关系 我没有太多地与django管理员打交道,所以我不完全确定如何让它工作。以下是我失败的尝试: class CreateSpecializedProfileAdminForm(forms.ModelForm): class Meta: exclude = ['pr
class CreateSpecializedProfileAdminForm(forms.ModelForm):
class Meta:
exclude = ['profile']
first_name = forms.CharField(max_length=30)
last_name = forms.CharField(max_length=30)
email = forms.EmailField(max_length=30)
password = forms.CharField(max_length=30)
confirm_password = forms.CharField(max_length=30)
def clean(self):
password = self.cleaned_data['password']
confirm_password = self.cleaned_data['confirm_password']
if len(self.cleaned_data['password']) < 6:
raise forms.ValidationError('Password must be at least 6 characters.')
if password != confirm_password:
raise forms.ValidationError('Passwords must match.')
return super(CreateSpecializedProfileAdminForm, self).clean()
def save(self, commit=True):
from django.contrib.auth.models import User
first = self.cleaned_data['first_name']
last = self.cleaned_data['last_name']
email = self.cleaned_data['email']
password = self.cleaned_data['password']
user = User.objects.create_user(email, email, password)
user.first_name = first
user.last_name = last
user.save()
profile = UserProfile()
profile.user_auth = user
profile.save()
specialized_profile = SpecializedProfile()
specialized_profile.profile = profile
specialized_profile.save()
return specialized_profile
class SpecializedProfileAdmin(admin.ModelAdmin):
form = CreateSpecializedProfileAdminForm
admin.site.register(SpecializedProfile, SpecializedProfileAdmin)
删除类Meta并将exclude=['profile']移动到ModelAdmin
class SpecializedProfileAdmin(admin.ModelAdmin):
exclude = ['profile']
form = CreateSpecializedProfileAdminForm