django模板循环集合.defaultdict（lambda:collections.defaultdict（list））

在我看来，我从queryset创建了以下列表字典

#view.py
queryset = MyModel.objects.filter(owner=user, dashboard=tab).order_by('position')
my_dict = collections.defaultdict(lambda: collections.defaultdict(list))    
for obj in queryset:
    my_dict[int(obj.position.split('-')[0])][int(obj.position.split('-')[2])].append(obj)
return Response({'queryset': dict(my_dict)}, template_name='dashboard/_maps_tab.html')

位置字段是一个字符字段，格式如下：X-X-X-X用于创建my_dict

我的字典是

--[1] #group
----[1] #col 1
------ object1.1.1 #group.col.pk
------ object1.1.2
------ object1.1.3
----[2] #col 2
------ object1.2.4
----[3] #col3
------ object1.3.5
------ object1.3.6

--[2] #group
----[1] #col 1
------object2.1.7 #group.col.pk

--[3] #group
----[1] #col1
------ object3.1.8 #group.col.pk
----[2] #col2
------object3.2.9
------object3.2.10

在我的模板中我想做什么

{% for groups in queryset.iteritems %}

    groups = {{ groups }} <br>

    {% for cols in groups %}

      cols = {{ cols }} <br>

      {% for objs in cols %}

        {{ objs }} in <br><br>

        {% for obj in objs %}        
          {{ obj.title }}, 
          {{ obj.desc}}, 
          {{ obj.fieldN }},         

        {% endfor %}

      {% endfor %}


    {% endfor %}

{% endfor %}

我怎样才能解决这个问题

提前谢谢

---

D

我的view.py解决方案是：

    my_dict = collections.defaultdict(lambda: collections.defaultdict(list))

    for obj in queryset:
        my_dict[int(obj.position.split('-')[0])][int(obj.position.split('-')[2])].append(obj)

    for obj in my_dict:            
        my_dict[obj].default_factory = None

    return Response({'queryset': dict(my_dict)}, template_name='_internal_template.html')

链接到和

我的模板

{% for groups in queryset.itervalues  %}

    groups = {{ groups }}    
    <br><br>

    {% for cols in groups.itervalues  %}

      cols = {{ cols }}    
      <br><br>

      {% for obj in cols  %}

        obj = {{ obj}} in <br><br>
        obj info = {{ obj.title }}, {{ obj.abstract }}<br>

      {% endfor %}      

    {% endfor %}

{% endfor %}

{queryset.itervalues%中的组的%
组={{groups}}



{groups.itervalues%}
cols={{cols}}



{cols%中obj的%s}
obj={{obj}}in


obj info={{obj.title}}，{{{obj.abstract}}}

{%endfor%}
{%endfor%}
{%endfor%}

Use我从未为此使用过django mptt，很高兴知道。我必须保留dict结构，因为它将加载一个复杂的HTML/jQuery页面

    my_dict = collections.defaultdict(lambda: collections.defaultdict(list))

    for obj in queryset:
        my_dict[int(obj.position.split('-')[0])][int(obj.position.split('-')[2])].append(obj)

    for obj in my_dict:            
        my_dict[obj].default_factory = None

    return Response({'queryset': dict(my_dict)}, template_name='_internal_template.html')

{% for groups in queryset.itervalues  %}

    groups = {{ groups }}    
    <br><br>

    {% for cols in groups.itervalues  %}

      cols = {{ cols }}    
      <br><br>

      {% for obj in cols  %}

        obj = {{ obj}} in <br><br>
        obj info = {{ obj.title }}, {{ obj.abstract }}<br>

      {% endfor %}      

    {% endfor %}

{% endfor %}