docker容器id的生成方式
我想知道容器id是如何生成的,所以请提供执行docker运行时提供容器id的源代码?以下是docker daemon用于创建容器的函数的代码片段:docker容器id的生成方式,docker,Docker,我想知道容器id是如何生成的,所以请提供执行docker运行时提供容器id的源代码?以下是docker daemon用于创建容器的函数的代码片段: func (daemon *Daemon) newContainer(name string, config *runconfig.Config, imgID string) (*Container, error) { var ( id string err error ) id, name,
func (daemon *Daemon) newContainer(name string, config *runconfig.Config, imgID string) (*Container, error) {
var (
id string
err error
)
id, name, err = daemon.generateIDAndName(name)
if err != nil {
return nil, err
}
…
base := daemon.newBaseContainer(id)
…
base.ExecDriver = daemon.execDriver.Name()
return &base, err
}
因此,创建ID和名称的逻辑在generateIDAndName函数中:
func (daemon *Daemon) generateIDAndName(name string) (string, string, error) {
var (
err error
id = stringid.GenerateNonCryptoID()
)
if name == "" {
if name, err = daemon.generateNewName(id); err != nil {
return "", "", err
}
return id, name, nil
}
if name, err = daemon.reserveName(id, name); err != nil {
return "", "", err
}
return id, name, nil
}
以下是具体方法,输入参数为false:
func generateID(crypto bool) string {
b := make([]byte, 32)
var r io.Reader = random.Reader
if crypto {
r = rand.Reader
}
for {
if _, err := io.ReadFull(r, b); err != nil {
panic(err) // This shouldn't happen
}
id := hex.EncodeToString(b)
// if we try to parse the truncated for as an int and we don't have
// an error then the value is all numberic and causes issues when
// used as a hostname. ref #3869
if _, err := strconv.ParseInt(TruncateID(id), 10, 64); err == nil {
continue
}
return id
}
}
如您所见,该值是随机生成的
// Reader is a global, shared instance of a pseudorandom bytes generator.
// It doesn't consume entropy.
var Reader io.Reader = &reader{rnd: Rand}