Doctrine 原则：executeQuery（）会添加额外的值作为回报

当我运行以下查询时：

$where = array(
    $request->get("order_item_id"), //an array with integers
);
$types = array(
    \Doctrine\DBAL\Connection::PARAM_INT_ARRAY
);

$sql = "SELECT id,store_id FROM order_items WHERE id IN (?) ORDER BY id";
$query = $app['db']->executeQuery($sql, $where, $types);
$order_items = $query->fetchAll();

我明白了：

Array
(
    [0] => Array
        (
            [id] => 1
            [0] => 1
            [store_id] => 11
            [1] => 11
        )

    [1] => Array
        (
            [id] => 6
            [0] => 6
            [store_id] => 11
            [1] => 11
        )

    [2] => Array
        (
            [id] => 11
            [0] => 11
            [store_id] => 11
            [1] => 11
        )

我不明白为什么要返回额外的0和1 VAL。

试试：

$order_items = $query->fetchAssoc();

对于一行，只返回字段名

---

或者尝试将PDO:：FETCH_ASSOC传递给fetchAll（）函数。

成功了！谢谢：$order\u items=$query->fetchAll（\PDO:：FETCH\u ASSOC）；