Error handling '；字符串'；不符合协议'；收集类型'；Swift 2.0中的错误

我刚下载了XCode Beta 7，收到错误“Type'String'不符合协议'CollectionType'”。这是我第一次尝试编码，所以我不知道如何解决这个问题。谢谢你

//the Pasteboard is nil if full access is not granted
            let pbWrapped: UIPasteboard? = UIPasteboard.generalPasteboard()
            if let pb = pbWrapped {
                var type = UIPasteboardTypeListImage[0] as! String
                if (count(type) > 0) && (image != nil) {
                    pb.setData(UIImagePNGRepresentation(image!)!, forPasteboardType: type)
                    var readDataWrapped: NSData? = pb.dataForPasteboardType(type)
                    if let readData = readDataWrapped {
                        var readImage = UIImage(data: readData, scale: 2)
                        print("\(image) == \(pb.image) == \(readImage)")
                    }
                }
            }

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只是一个关于从哪里开始了解这个问题的建议。。。 Swift 2中的字符串将其更改为：

type.characters.count

然后，您的代码应为：

//the Pasteboard is nil if full access is not granted
        let pbWrapped: UIPasteboard? = UIPasteboard.generalPasteboard()
        if let pb = pbWrapped {
            var type = UIPasteboardTypeListImage[0] as! String
            if (type.characters.count > 0) && (image != nil) {
                pb.setData(UIImagePNGRepresentation(image!)!, forPasteboardType: type)
                var readDataWrapped: NSData? = pb.dataForPasteboardType(type)
                if let readData = readDataWrapped {
                    var readImage = UIImage(data: readData, scale: 2)
                    print("\(image) == \(pb.image) == \(readImage)")
                }
            }
        }

---

哪一行给出了错误？@PhillipMills if（count（type）>0）和&（image！=nil）{请特别注意接受答案中有关Swift 2更改的注释。@PhillipMills，谢谢！但是，我对如何实现这一点仍然有点困惑（我是编写应用程序的新手，我几天前才开始学习）根据这个答案——我没有试过——建议是：

if（type.characters.count>0）&（image！=nil）{

。