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Excel 无列老化配方奶粉天数(天)_Excel_Excel Formula - Fatal编程技术网

Excel 无列老化配方奶粉天数(天)

Excel 无列老化配方奶粉天数(天),excel,excel-formula,Excel,Excel Formula,我想在列中添加Aging grop,而不使用老化天数。因此,我可以在单列而不是两步计算中得到帮助 天数的公式为 Doc. Date Aging (days) Aging class 10/06/2010 1820 121+ Days 09/30/2015 0 0 - 30 Days 09/11/2015 19 0 - 30 Days 09/11/2015 19 0 - 30 D

我想在列中添加Aging grop,而不使用老化天数。因此,我可以在单列而不是两步计算中得到帮助

天数的公式为

Doc. Date   Aging (days)    Aging class
10/06/2010  1820            121+ Days
09/30/2015  0               0 - 30 Days
09/11/2015  19              0 - 30 Days
09/11/2015  19              0 - 30 Days
09/11/2015  19              0 - 30 Days
09/11/2015  19              0 - 30 Days
老年组的配方为

=IF(ISBLANK(H4),"",'Ex. rate'!$G$2-I4)
=如果(J4警告)它很长:

=IF(J4<=30,"0 - 30 Days",IF(J4<=60,"31 - 60 Days",IF(J4<=90,"61 - 90 Days",IF(J4<=120,"91 - 120 Days","121+ Days"))))
=IF(ISBLANK(H4),“”,IF('Ex.rate')!$G$2-I4或者:(没有嵌套的IF,但始终需要相同的范围)


(将H4改为I4)…对我来说仍然非常有效。不知道它怎么会错…抱歉://

…它看起来不错,但不知道为什么它对我不起作用它只显示0-30天。而且它应该是H4而不是I4。我已经转移了列,忘记了编辑。
=IF(ISBLANK(H4),"",IF('Ex. rate'!$G$2-I4<=30,"0 - 30 Days",IF('Ex. rate'!$G$2-I4<=60,"31 - 60 Days",IF('Ex. rate'!$G$2-I4<=90,"61 - 90 Days",IF('Ex. rate'!$G$2-I4<=120,"91 - 120 Days","121+ Days")))))
=IF(I4="","",CHOOSE(MIN(MAX(TRUNC(('Ex. rate'!$G$2-I4-1)/30)+1,1),5),"0 - 30 Days","31 - 60 Days","61 - 90 Days","91 - 120 Days","121+ Days"))