Warning: file_get_contents(/data/phpspider/zhask/data//catemap/3/reactjs/21.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Excel VbScript抛出一个错误";未知运行时错误“;_Excel_Vbscript_Vba - Fatal编程技术网

Excel VbScript抛出一个错误";未知运行时错误“;

Excel VbScript抛出一个错误";未知运行时错误“;,excel,vbscript,vba,Excel,Vbscript,Vba,我编写了一个代码来删除excel工作表中的行,但它给了我一个错误,如主题中所述 代码 Sub ChildPidDelt(ob3,DeletArr) Dim height,row,str,i Dim dataArray Dim d height = objExcel1.Application.WorksheetFunction.CountA(ob3.Columns(1)) 'MsgBox(height) ReDim dataArray(height - 2, 0) ' -1 for 0 ind

我编写了一个代码来删除excel工作表中的行,但它给了我一个错误,如主题中所述

代码

 Sub ChildPidDelt(ob3,DeletArr)

Dim height,row,str,i
Dim dataArray
Dim d
height = objExcel1.Application.WorksheetFunction.CountA(ob3.Columns(1))
'MsgBox(height)
ReDim dataArray(height - 2, 0) ' -1 for 0 index, -1 for the first row as header row, excluded
str = ""
dataArray = ob3.Range(ob3.Cells(2, 1),ob3.Cells(height, 1)).Value
Set d = CreateObject("scripting.dictionary")
MsgBox(LBound(DeletArr) & ":" & UBound(DeletArr))
For i = LBound(DeletArr) To UBound(DeletArr)
    If Not d.exists(DeletArr(i)) Then
        d(DeletArr(i)) =  0
    End If
Next
MsgBox(LBound(dataArray,1) & ":" & UBound(dataArray,1))
For i = LBound(dataArray, 1) To UBound(dataArray, 1)
    If d.exists(dataArray(i, 1)) Then

        str = str & (i+1) & ":" & (i+1) & ","

    Else
        'found = False
    End If
Next
If Len(str) > 0 Then
    MsgBox(Len(str))
    str = Mid(str, 1, Len(str) - 1)
    MsgBox(str)
    ob3.Range(str).Delete

End If

End Sub
请在下面找到调试屏幕:

你能帮我解释一下原因吗?

Range()
无法处理超过255个字符的字符串

您可以通过将删除内容分解为多个部分来解决此问题。这里有一个简单的方法:直接放在最后一个msgbox之后

dim x
dim rangesToRemove
rangesToRemove = Split(str,",")
for x = UBOUND(rangesToRemove) to LBOUND(RangesToRemove) Step -1
   ob3.Range(rangesToRemove(x)).delete
next
编辑:好的,根据你的评论,这里有一种更复杂的方法,可以将删除内容分解成块

dim x
dim rangesToRemove
dim strToRemove : strToRemove = ""
rangesToRemove = Split(str,",")
for x = UBOUND(rangesToRemove) to LBOUND(RangesToRemove) Step -1
   strToRemove = strToRemove & rangesToRemove(x)
   If Len(strToRemove) > 200 then
       ob3.Range(strToRemove).delete
       strToRemove = ""
   else
       strToRemove = strToRemove & ","
   end if
next
If len(strToRemove) > 0 then
   strToRemove = Left(strToRemove, Len(strToRemove) -1)
   ob3.Range(strToRemove).delete
end if

通过这种方式删除行,无论如何都可以删除不需要的行,因为删除会导致行向上移动,对吗?有没有更快的流程?它会一个接一个地删除,对吗?很明显,你可以把它分成几块。。。我费心更新以展示一种可能的方法。很好的一种,只是为了确认-它是
UBOUND(rangesToRemove)
还是
UBOUND(rangesToRemove)-1
?请按照您所说的查看修改后的代码,但我还是把它弄坏了!但是没有进步!