Excel p> 代码 Sub testWhat() Dim dTime As Double dTime = Timer Const sName As String = "Sheet1" Const sFirst As String

p> 代码

Sub testWhat()
Dim dTime As Double
dTime = Timer
    Const sName As String = "Sheet1"
    Const sFirst As String = "A1"
    Const dName As String = "Sheet1"
    Const dFirst As String = "C1"
    Dim srg As Range: Set srg = ThisWorkbook.Worksheets(sName).Range(sFirst)
    Dim drg As Range: Set drg = ThisWorkbook.Worksheets(dName).Range(dFirst)
    sadTest srg, drg
Debug.Print Timer - dTime
End Sub

Sub sadTest(sCell As Range, dcell As Range)
    Dim rg As Range
    With sCell.CurrentRegion
        Set rg = .Columns(1).Resize(.Rows.Count - 1).Offset(1)
    End With
    Dim kData As Variant: kData = rg.Value
    Dim vData As Variant: vData = rg.Offset(, 1).Value
    Dim dict As Object: Set dict = CreateObject("Scripting.Dictionary")
    Dim arl As Object: Set arl = CreateObject("System.Collections.ArrayList")
    Dim srCount As Long: srCount = UBound(kData, 1)
    Dim drCount As Long: drCount = 1
    Dim rData As Variant: ReDim rData(1 To srCount)
    Dim Key As Variant
    Dim dCount As Long
    Dim i As Long
    For i = 1 To srCount
        Key = kData(i, 1)
        If dict.Exists(Key) Then
            dCount = dict(Key) + 1
            rData(i) = dCount
            dict(Key) = dCount
            If dCount > drCount Then
                drCount = drCount + 1
            End If
        Else
            arl.Add Key
            dict(Key) = 1
            rData(i) = 1
        End If
    Next i
    Dim dcCount As Long: dcCount = dict.Count
    
    ' arl.IndexOf(kData(i, 1), 0) + 1
    ' Application.Match(kData(i, 1), dict.keys, 0) ' to slow
    
    Dim Result As Variant: ReDim Result(1 To drCount, 1 To dcCount)
    For i = 1 To srCount
        Result(rData(i), arl.IndexOf(kData(i, 1), 0) + 1) = vData(i, 1)
    Next i
    
    dcell.Resize(drCount, dcCount).Value = Result
 
End Sub

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将namedworkbook | thisworkbook.namedsheet.Range（“A2:B”&m）读入数组。Redim

a

（1到1，1到iif（m=2,2，m-1））外部环路。通过循环数组而不是表填充。在工作表引用中要明确。将

v

as（）声明为string当

ubound v=-1

为no时会发生什么”，“在

a（1，c）

中？事实上，代码是用来演示解决方案的（但我认为这不是最好的方法）。有更好的解决办法吗？@TimWilliams是的。我说错了。我的错误。将namedworkbook | thisworkbook.namedsheet.Range（“A2:B”&m）读入数组。Redim

a

（1到1，1到iif（m=2,2，m-1））外部环路。通过循环数组而不是表填充。在工作表引用中要明确。将

v

as（）声明为string当

ubound v=-1

为no时会发生什么”，“在

a（1，c）

中？事实上，代码是用来演示解决方案的（但我认为这不是最好的方法）。有更好的解决办法吗？@TimWilliams是的。我说错了。我的错，非常感谢。那也太棒了。非常感谢。那也太棒了。非常感谢。太棒了，太谢谢你了。太棒了。

Option Explicit

Public Sub WriteOutValuesByKeyColumn()
    Dim columnMapping As Scripting.dictionary, targetSheet As Worksheet
    
    Set targetSheet = ThisWorkbook.Worksheets("Sheet1")
    Set columnMapping = New Scripting.dictionary 'qualify with class
    
    With targetSheet
        
        Dim lastRow As Long
        
        lastRow = .Cells(.Rows.Count, "A").End(xlUp).Row
        
        Dim inputArray() As Variant, tempArray() As Variant
        
        inputArray = .Range("A2:B" & lastRow).Value
        
        ReDim tempArray(1 To 1, 1 To IIf(lastRow = 2, 2, lastRow - 1)) 'max size array at start

        Dim i As Long, counter As Long
        
        For i = LBound(inputArray, 1) To UBound(inputArray, 1)
        
            If Not columnMapping.Exists(inputArray(i, 1)) Then
            
                counter = counter + 1
                tempArray(1, counter) = inputArray(i, 2)
                columnMapping.Add inputArray(i, 1), counter
                
            Else
            
                tempArray(1, columnMapping.Item(inputArray(i, 1))) = tempArray(1, columnMapping.Item(inputArray(i, 1))) & ", " & inputArray(i, 2)
                
            End If
            
        Next
        
        Dim columnValues() As String
       
        For i = 1 To UBound(tempArray, 2)
        
            If tempArray(1, i) <> vbNullString Then
                
                columnValues = Split(tempArray(1, i), ", ")
                .Cells(1, i + 2).Resize(UBound(columnValues, 1) + 1).Value = WorksheetFunction.Transpose(columnValues)
                
            Else
            
                .Cells(1, i + 2) = tempArray(1, i)
                
            End If
            
        Next
    
    End With
End Sub

Sub testWhat()
Dim dTime As Double
dTime = Timer
    Const sName As String = "Sheet1"
    Const sFirst As String = "A1"
    Const dName As String = "Sheet1"
    Const dFirst As String = "C1"
    Dim srg As Range: Set srg = ThisWorkbook.Worksheets(sName).Range(sFirst)
    Dim drg As Range: Set drg = ThisWorkbook.Worksheets(dName).Range(dFirst)
    sadTest srg, drg
Debug.Print Timer - dTime
End Sub

Sub sadTest(sCell As Range, dcell As Range)
    Dim rg As Range
    With sCell.CurrentRegion
        Set rg = .Columns(1).Resize(.Rows.Count - 1).Offset(1)
    End With
    Dim kData As Variant: kData = rg.Value
    Dim vData As Variant: vData = rg.Offset(, 1).Value
    Dim dict As Object: Set dict = CreateObject("Scripting.Dictionary")
    Dim arl As Object: Set arl = CreateObject("System.Collections.ArrayList")
    Dim srCount As Long: srCount = UBound(kData, 1)
    Dim drCount As Long: drCount = 1
    Dim rData As Variant: ReDim rData(1 To srCount)
    Dim Key As Variant
    Dim dCount As Long
    Dim i As Long
    For i = 1 To srCount
        Key = kData(i, 1)
        If dict.Exists(Key) Then
            dCount = dict(Key) + 1
            rData(i) = dCount
            dict(Key) = dCount
            If dCount > drCount Then
                drCount = drCount + 1
            End If
        Else
            arl.Add Key
            dict(Key) = 1
            rData(i) = 1
        End If
    Next i
    Dim dcCount As Long: dcCount = dict.Count
    
    ' arl.IndexOf(kData(i, 1), 0) + 1
    ' Application.Match(kData(i, 1), dict.keys, 0) ' to slow
    
    Dim Result As Variant: ReDim Result(1 To drCount, 1 To dcCount)
    For i = 1 To srCount
        Result(rData(i), arl.IndexOf(kData(i, 1), 0) + 1) = vData(i, 1)
    Next i
    
    dcell.Resize(drCount, dcCount).Value = Result
 
End Sub