Express sequelize创建db记录后,如何从响应中删除json元素?
使用sequelize,我可以使用Express sequelize创建db记录后,如何从响应中删除json元素?,express,sequelize.js,Express,Sequelize.js,使用sequelize,我可以使用productmodek在数据库中创建product,但我想编辑json响应,删除updatedAt和createdAt元素。我该怎么做 我的代码: router.post('/products', (req, res, next) => { Product.create({ name: req.body.name, price: req.body.price }).then( product
product
modek在数据库中创建product
,但我想编辑json响应,删除updatedAt和createdAt元素。我该怎么做
我的代码:
router.post('/products', (req, res, next) => {
Product.create({
name: req.body.name,
price: req.body.price
}).then(
product => res.status(200)
.json(product)
)
});
调用localhost:3000/具有此正文的产品时:
{
"name": "A Book",
"price": 10.99,
}
我得到的回应是:
{
"id": 8,
"name": "A Book",
"price": 10.99,
"updatedAt": "2018-06-26T20:09:38.643Z", <-- Remove?
"createdAt": "2018-06-26T20:09:38.643Z" <-- Remove?
}
{
“id”:8,
“名称”:“一本书”,
“价格”:10.99,
“updatedAt”:“2018-06-26T20:09:38.643Z”,尝试使用pick()
如果你的回答是
{
"id": 8,
"name": "A Book",
"price": 10.99,
"updatedAt": "2018-06-26T20:09:38.643Z",
"createdAt": "2018-06-26T20:09:38.643Z"
}
试试看,var result=u.pick(响应,[“名称”,“价格]);
router.post('/products', (req, res, next) => {
Product.create({
name: req.body.name,
price: req.body.price
}).then(
product =>
var result = _.pick(response, ["name", "price"]);
res.status(200).json(result)
)
});