File 复制文件时,如何根据工作表名称更改google工作表中单元格的值?
我想在谷歌驱动器文件夹中复制源文件(谷歌工作表)100次。这是我的剧本:File 复制文件时,如何根据工作表名称更改google工作表中单元格的值?,file,google-apps-script,google-sheets,duplicates,filenames,File,Google Apps Script,Google Sheets,Duplicates,Filenames,我想在谷歌驱动器文件夹中复制源文件(谷歌工作表)100次。这是我的剧本: function copyfilefromsource() { var ui = SpreadsheetApp.getUi(); var sheet_merge = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("List"); var last_row = sheet_merge.getLastRow(); var newsh
function copyfilefromsource() {
var ui = SpreadsheetApp.getUi();
var sheet_merge = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("List");
var last_row = sheet_merge.getLastRow();
var newsheet_firstname = null;
var newsheet_surname = null;
var newsheet_email = null;
var source_folder = null;
var file_owner = null;
var dest_folder = null;
var sheets_created = 0;
var new_file = null;
var source_file = null;
var employee_id = null;
var google_domain = null;
var range = sheet_merge.getRange(1, 1, last_row, 4);
var temp = null;
source_file = DriveApp.getFileById(range.getCell(1, 2).getValue());
dest_folder = DriveApp.getFolderById(range.getCell(2, 2).getValue());
file_owner = range.getCell(3, 2).getValue();
google_domain = range.getCell(4, 2).getValue();
if (last_row <= 6) {
SpreadsheetApp.getUi().alert("No rows to process!");
return
}
for (var i = 7; i <= last_row; i++) {
if (range.getCell(i, 4).getValue() == '') {
employee_id = range.getCell(i, 1).getValue();
newsheet_email = employee_id + google_domain;
newsheet_firstname = range.getCell(i, 2).getValue();
newsheet_surname = range.getCell(i, 3).getValue();
new_file = source_file.makeCopy(employee_id, dest_folder);
new_file.setOwner(file_owner);
new_file.addViewer(newsheet_email);
new_file.setSharing(DriveApp.Access.ANYONE_WITH_LINK, DriveApp.Permission.EDIT);
SpreadsheetApp.getActiveSheet().getRange(i,1).setFormula('=HYPERLINK("' + new_file.getUrl() +'/","'+employee_id+'")');
SpreadsheetApp.getActiveSheet().getRange(i,4).setValue(new_file.getId());
sheets_created++;
}
}
ui.alert(sheets_created + " files were created!")
}
function testFolder(folderName){
var exist = true;
try{var testFolder = DocsList.getFolder(folderName)}
catch(err){exist=false}
return exist;
}
函数copyfilefromsource(){
var ui=SpreadsheetApp.getUi();
var sheet_merge=SpreadsheetApp.getActiveSpreadsheet().getSheetByName(“列表”);
var last_row=sheet_merge.getLastRow();
var newsheet_firstname=null;
var newsheet_姓氏=null;
var newsheet_email=null;
var source_folder=null;
var file_owner=null;
var dest_folder=null;
已创建的风险值=0;
var new_file=null;
var source_file=null;
var employee_id=null;
var google_domain=null;
var range=sheet\u merge.getRange(1,1,最后一行,4);
var-temp=null;
source_file=DriveApp.getFileById(range.getCell(1,2.getValue());
dest_folder=DriveApp.getFolderById(range.getCell(2,2.getValue());
file_owner=range.getCell(3,2).getValue();
google_domain=range.getCell(4,2.getValue();
如果(最后一行尝试以下操作:
//...
//after this line of your code :
new_file.setSharing(DriveApp.Access.ANYONE_WITH_LINK, DriveApp.Permission.EDIT);
//add :
var id_ss = new_file.getId();
SpreadsheetApp.openById(id_ss).getSheets()[0].getRange(2, 2).setValue(employee_id);
小贴士:不要把它当成个人的,但你的代码乱七八糟……你可以把它清理干净;)Hi Waxim,谢谢你的回复。很抱歉代码太乱了。我已经添加了你提供的代码。但是,它表明new\u file.getSheets
不是一个函数。这是我运行脚本时出现的错误:TypeError:new\u file.getSheets不是一个函数
你知道为什么它不工作吗?你说得对,我的错,makeCopy返回的是文件,而不是我想象中的电子表格。我编辑了anwserThanks Waxim,现在它工作得很好!因此基本上,对于创建的每个工作表,您希望在单元格中设置其idB2
?