Firebase函数从存储器中获取文件
我必须向API发送一个文件,因此我必须使用Firebase函数从存储器中获取文件,firebase,google-cloud-functions,Firebase,Google Cloud Functions,我必须向API发送一个文件,因此我必须使用fs.readFileSync()。将图片上传到存储器后,我调用我的函数来执行API调用。但我无法从存储器中获取文件。这是代码的一部分,它在结果中总是为null。我还尝试在没有参数的情况下.getFiles(),然后我得到了所有文件,但我不想通过迭代过滤它们 exports.stripe_uploadIDs = functions.https //.region("europe-west1") .onCall((data, context)
fs.readFileSync()
。将图片上传到存储器后,我调用我的函数来执行API调用。但我无法从存储器中获取文件。这是代码的一部分,它在结果中总是为null。我还尝试在没有参数的情况下.getFiles()
,然后我得到了所有文件,但我不想通过迭代过滤它们
exports.stripe_uploadIDs = functions.https //.region("europe-west1")
.onCall((data, context) => {
const authID = context.auth.uid;
console.log("request is authentificated? :" + authID);
if (!authID) {
throw new functions.https.HttpsError("not authorized", "not authorized");
}
let accountID;
let result_fileUpload;
let tempFile = path.join(os.tmpdir(), "id_front.jpg");
const options_id_front_jpeg = {
prefix: "/user/" + authID + "/id_front.jpg"
};
const storageRef = admin
.storage()
.bucket()
.getFiles(options_id_front)
.then(results => {
console.log("JPG" + JSON.stringify(results));
// need to write this file to tempFile
return results;
});
const paymentRef = storageRef.then(() => {
return admin
.database()
.ref("Payment/" + authID)
.child("accountID")
.once("value");
});
const setAccountID = paymentRef.then(snap => {
accountID = snap.val();
return accountID;
});
const fileUpload = setAccountID.then(() => {
return Stripe.fileUploads.create(
{
purpose: "identity_document",
file: {
data: tempFile, // Documentation says I should use fs.readFileSync("filepath")
name: "id_front.jpg",
type: "application/octet-stream"
}
},
{ stripe_account: accountID }
);
});
const fileResult = fileUpload.then(result => {
result_fileUpload = result;
console.log(JSON.stringify(result_fileUpload));
return result_fileUpload;
});
return fileResult;
});
结果是:
JPG[[]]
您需要将文件从bucket下载到本地函数context env。 Firebase函数开始执行后,可以调用以下命令: 下面的内容或多或少都会起作用,只要根据您的需要调整即可。在你的
中调用它。一旦调用上下文,你就明白了
import admin from 'firebase-admin';
import * as path from 'path';
import * as os from 'os';
import * as fs from 'fs';
admin.initializeApp();
const { log } = console;
async function tempFile(fileBucket: string, filePath: string) {
const bucket = admin.storage().bucket(fileBucket);
const fileName = 'MyFile.ext';
const tempFilePath = path.join(os.tmpdir(), fileName);
const metadata = {
contentType: 'DONT_FORGET_CONTEN_TYPE'
};
// Donwload the file to a local temp file
// Do whatever you need with it
await bucket.file(filePath).download({ destination: tempFilePath });
log('File downloaded to', tempFilePath);
// After you done and if you need to upload the modified file back to your
// bucket then uploaded
// This is optional
await bucket.upload(tempFilePath, {
destination: filePath,
metadata: metadata
});
//free up disk space by realseasing the file.
// Otherwise you might be charged extra for keeping memory space
return fs.unlinkSync(tempFilePath);
}
我不清楚你在这里想干什么。你的代码片段不是一个完整的云函数定义,这并没有帮助——我不知道它是什么类型的触发器。你能把你的问题编辑得更清楚些吗?我已经更新了代码听起来好像你想在你创建的文件对象上使用download()。