如何将Firebase Swift 3模棱两可的引用传递给成员'；观察（用）和#x27；错误？

我知道过去有人问过这个问题，但我无法找到一个适用于swift 3的解决方案。谁能给我指一下正确的方向吗。这是我的密码：

    ref.child(uid).child("flights").observe(.value, with:{  (snapshot: FIRDataSnapshot!) -> Void in
        self.messages.append(snapshot)

        let row = [IndexPath(row: self.messages.count-1, section: 0) ]


        print(snapshot)

        self.flightTableView.insertRows(at: row, with: .automatic)

        DispatchQueue.main.async {
            self.flightTableView.reloadData()
        }
    })

}

---

我把代码分解成两个语句，它开始工作了

    let child:FIRDatabaseReference = ref.child(uid).child("flights")


    child.observe(.childAdded) { (snapshot:FIRDataSnapshot) in
        print(snapshot)
    }

---

我把代码分解成两个语句，它开始工作了

    let child:FIRDatabaseReference = ref.child(uid).child("flights")


    child.observe(.childAdded) { (snapshot:FIRDataSnapshot) in
        print(snapshot)
    }

---

Swift 3和Firebase 3.17.0

这样就可以了，试试下面的代码

        let ref = FIRDatabase.database().reference().child("uid").child("flights")
        ref.observe(.value, with: { (snapshot) in
            print("Success get the snapshot \(snapshot)")
            // do something with snapshot than
            DispatchQueue.main.async {
                self.yourTableView.reloadData()
            }
        }) { (error) in
            print("Failed get the snapshot \(error.localizedDescription)")
            // do something to handle error
        }

---

Swift 3和Firebase 3.17.0

这样就可以了，试试下面的代码

        let ref = FIRDatabase.database().reference().child("uid").child("flights")
        ref.observe(.value, with: { (snapshot) in
            print("Success get the snapshot \(snapshot)")
            // do something with snapshot than
            DispatchQueue.main.async {
                self.yourTableView.reloadData()
            }
        }) { (error) in
            print("Failed get the snapshot \(error.localizedDescription)")
            // do something to handle error
        }