F# 在这种情况下，如何处理序列构造，因为我们不'；没有中断也没有强大版本的Seq.choose？

我希望我能做到：

 let myFun param1 param2 = 
      .....
      if condition 1
          ....
          if condition 2
               yield ....

 let sequence = seq { for x in xs do
                            myFun 1 x
                            myFun 2 x
                    }

但现在我只能这样做

 let myFun param = 
      .....
      .....
      if condition 1
          ....
          if condition 2
               Some....
          else None    // has to complete else
      else None

 let sequence = seq { for x in xs do
                        match myFun 1 x with
                        | Some x -> yield x
                        | None   -> ()
                        match myFun 2 x with
                        | Some x -> yield x
                        | None   -> ()
                    }

  let sequence2 =  // order will be different, and we can not have index passed into function unless we do a futher Seq.map

       let a = xs |> Seq.choose (myFun 1)
       let b = xs |> Seq.choose (myFun 2)
       Seq.append a b

我的真实代码：

代码看起来不太好一些

None

，我尝试了

Seq.choose

，这没有多大帮助，因为它不支持

Seq.choosei

        let exam isForward brickID =
            let brick = state.[brickID]
            let (nextTR, nextOccupied, nextUnoccupied) = if isForward then brick.Body.nudgeForward () else brick.Body.nudgeBack ()
            if (nextOccupied.isInGrid gridSize) && (map.ContainsKey nextOccupied |> not) then
                let nextBrick = { brick with Body = nextTR }
                let nextState = getNextState state brickID nextBrick
                if not (explored.Contains nextState) then
                    let nextMap = map |> Map.remove nextUnoccupied
                                      |> Map.add nextOccupied nextBrick
                    Some ((nextState, nextMap), (nextBrick, if isForward then brick.Body.Direction else brick.Body.Direction.Opposite))
                else None
            else None

        seq { for brickID in 0 .. state.Length - 1 do
                match exam true brickID with
                | Some x -> yield x
                | None   -> ()
                match exam false brickID with
                | Some x -> yield x
                | None   -> ()
        }

---

您的

检查

函数可以返回一个序列，该序列要么为空（而不是

无

），要么只包含一个元素（而不是

某些

），并使用

屈服将给定序列的所有元素添加到当前生成的序列中

在您的伪代码示例中，如下所示：

let myFun param1 param2 param3 = seq {
  if param1 then
    if param2 then
      yield param3 }

 let sequence = seq { 
   for x in xs do
     yield! myFun true true x 
     yield! myFun true true (x * 10) }

假设
xs=[1；2]
上述示例生成
[1；10；2；20]
（如果您将一些
true
参数设置为
false
，它将跳过一些数字）
在本例中，@Tomas的答案是最好的方法。但是，您仍然可以从以下位置选择使用方便的功能：

您可以将其视为
Seq的自定义版本。选择

let sequence = seq { for x in xs do
                        yield! Option.toList (myFun 1 x)
                        yield! Option.toList (myFun 2 x)
                    }