Google bigquery BigQuery运行总计

我在BigQuery中运行总计时遇到问题

我在这里找到了一个有效的例子：

但我真正想做的是计算最流行的词的数量，这些词占总词数的80%。因此，我尝试在按word_count排序时首先计算运行总数：

SELECT word, word_count, SUM(word_count) OVER(ORDER BY word_count DESC)
FROM [publicdata:samples.shakespeare]
WHERE corpus  = 'hamlet'
AND word > 'a' LIMIT 30

但我明白了：

Row word    word_count  f0_  
1   o'er    18          18   
2   answer  13          31   
3   meet    8           39   
4   told    5           44   
5   treason 4           **52**   
6   quality 4           **52**   
7   brave   3           55  

运行总数没有从5号线增加到6号线。可能是因为在这两种情况下，单词数都是4

我做错了什么

也许有更好的办法？我的计划是计算总跑步量。然后将其除以sum（word_count）OVER（）并仅过滤小于80%的行。然后计算这些行的数量

首先，删除“LIMIT 30”-它将干扰OVER（）子句

你想要一个比例？尝试比率报告：

SELECT word, word_count, RATIO_TO_REPORT(word_count) OVER(ORDER BY word_count DESC)
FROM [publicdata:samples.shakespeare]
WHERE corpus  = 'hamlet'
AND word > 'a' 

是否希望具有相同值的连续行以任何方式增加？确定这些行的顺序，并使用次顺序：

SELECT word, word_count, RATIO_TO_REPORT(word_count) OVER(ORDER BY word_count DESC, word)
FROM [publicdata:samples.shakespeare]
WHERE corpus  = 'hamlet'
AND word > 'a' 

你想要涵盖80%的最流行词汇吗？将这些比率相加，过滤掉剩下的：

SELECT word, word_count, sum_ratio
FROM (
 SELECT word, word_count, SUM(ratio) OVER(ORDER BY ratio, word) sum_ratio
 FROM (
    SELECT word, word_count, RATIO_TO_REPORT(word_count) OVER(ORDER BY word_count DESC, word) ratio
    FROM [publicdata:samples.shakespeare]
    WHERE corpus  = 'hamlet'
    AND word > 'a' 
 )
)
WHERE sum_ratio>0.8

Row word    word_count  sum_ratio    
1   is      313         0.8125175752219499   
2   it      361         0.827019644076648    
3   in      400         0.8430884184308841   
4   my      441         0.8608042421564295   
5   you     499         0.8808500381633391   
6   of      630         0.906158357771261    
7   to      635         0.9316675370586108   
8   and     706         0.9600289237938375   
9   the     995         0.9999999999999999  

---

谢谢！这是一门真正的关于窗口函数的课程。

SELECT word, word_count, sum_ratio
FROM (
 SELECT word, word_count, SUM(ratio) OVER(ORDER BY ratio, word) sum_ratio
 FROM (
    SELECT word, word_count, RATIO_TO_REPORT(word_count) OVER(ORDER BY word_count DESC, word) ratio
    FROM [publicdata:samples.shakespeare]
    WHERE corpus  = 'hamlet'
    AND word > 'a' 
 )
)
WHERE sum_ratio>0.8

Row word    word_count  sum_ratio    
1   is      313         0.8125175752219499   
2   it      361         0.827019644076648    
3   in      400         0.8430884184308841   
4   my      441         0.8608042421564295   
5   you     499         0.8808500381633391   
6   of      630         0.906158357771261    
7   to      635         0.9316675370586108   
8   and     706         0.9600289237938375   
9   the     995         0.9999999999999999