GRAILS:查找自引用一对多关系中的所有子级
在圣杯中 如何找到一对多关系中的所有孩子,例如GRAILS:查找自引用一对多关系中的所有子级,grails,groovy,gorm,Grails,Groovy,Gorm,在圣杯中 如何找到一对多关系中的所有孩子,例如 class Employee { static hasMany = [ subordinates: Employee ] static belongsTo = [ manager: Employee ] } 使用单个管理器,如何获得所有下属的下属(如遍历对象图)?如果您不想修改域,递归闭包可以工作。否则,您可以向Employee域类添加一个临时属性,如本例中的allsubsiders: class Employee { S
class Employee {
static hasMany = [ subordinates: Employee ]
static belongsTo = [ manager: Employee ]
}
使用单个管理器,如何获得所有下属的下属(如遍历对象图)?如果您不想修改域,递归闭包可以工作。否则,您可以向
Employee
域类添加一个临时属性,如本例中的allsubsiders
:
class Employee {
String name
static hasMany = [ subordinates: Employee ]
static belongsTo = [ manager: Employee ]
static transients = ['allSubordinates']
def getAllSubordinates() {
return subordinates ? subordinates*.allSubordinates.flatten() + subordinates : []
}
}
下面是一个集成测试,以查看它的运行情况:
import grails.test.*
class EmployeeTests extends GrailsUnitTestCase {
Employee ceo
Employee middleManager1, middleManager2
Employee e1, e2, e3, e4, e5, e6
protected void setUp() {
super.setUp()
ceo = new Employee(name:"CEO")
middleManager1 = new Employee(name:"Middle Manager 1")
e1 = new Employee(name:"e1")
e2 = new Employee(name:"e2")
e3 = new Employee(name:"e3")
middleManager2 = new Employee(name:"Middle Manager 2")
e4 = new Employee(name:"e4")
e5 = new Employee(name:"e5")
e6 = new Employee(name:"e6")
ceo.subordinates = [middleManager1, middleManager2]
middleManager1.subordinates = [e1,e2,e3]
middleManager2.subordinates = [e4,e5,e6]
assert ceo.save()
}
void testAllSubordinates() {
def topLevelManager = Employee.get(ceo.id)
assertNotNull(topLevelManager);
assertEquals(8, topLevelManager.allSubordinates?.size())
}
}
import grails.test.*
class EmployeeTests extends GrailsUnitTestCase {
Employee ceo
Employee middleManager1, middleManager2
Employee e1, e2, e3, e4, e5, e6
protected void setUp() {
super.setUp()
ceo = new Employee(name:"CEO")
middleManager1 = new Employee(name:"Middle Manager 1")
e1 = new Employee(name:"e1")
e2 = new Employee(name:"e2")
e3 = new Employee(name:"e3")
middleManager2 = new Employee(name:"Middle Manager 2")
e4 = new Employee(name:"e4")
e5 = new Employee(name:"e5")
e6 = new Employee(name:"e6")
ceo.subordinates = [middleManager1, middleManager2]
middleManager1.subordinates = [e1,e2,e3]
middleManager2.subordinates = [e4,e5,e6]
assert ceo.save()
}
void testAllSubordinates() {
def topLevelManager = Employee.get(ceo.id)
assertNotNull(topLevelManager);
assertEquals(8, topLevelManager.allSubordinates?.size())
}
}