为来自具有对象数组的API的响应创建graphql架构

我从一个Api得到如下响应：

property: Array(100)
0: {identifier: {…}, address: {…}, location: {…}, vintage: {…}}
1: {identifier: {…}, address: {…}, location: {…}, vintage: {…}}
2: {identifier: {…}, address: {…}, location: {…}, vintage: {…}}
3: {identifier: {…}, address: {…}, location: {…}, vintage: {…}}

我想在address对象中列出一些指定的字段，例如仅country和oneLine，但用于属性的每个索引

排列

address:
country: "US"
countrySubd: "CA"
line1: "1702 ELKHORN RD"
line2: "ROYAL OAKS, CA 95076"
locality: "Royal Oaks"
matchCode: "ExaStr"
oneLine: "1702 ELKHORN RD, ROYAL OAKS, CA 95076"
postal1: "95076"
postal2: "9218"
postal3: "R002"

我已经为如何在我的graphql模式页面中为此编写模式苦苦挣扎了两天。谁能帮帮我吗

这是我一直在尝试的，但一直在为数据获取空值

require("es6-promise").polyfill();
require("isomorphic-fetch");

const {
  GraphQLString,
  GraphQLList,
  GraphQLSchema,
  GraphQLObjectType,
  GraphQLInt
} = require("graphql");



const Identifier = new GraphQLObjectType({
  name: "identifier",
  fields: () => ({
    obPropId: { type: GraphQLInt }
  })
});

const AddressType = new GraphQLObjectType({
    name: 'Address',
    fields: () => ({
        country: { type: GraphQLString },
        oneLine: {type: GraphQLString }

    })
})

const RootQuery = new GraphQLObjectType({
  name: "RootQueryType",
  fields: {
    property: {
      type: new GraphQLList(Identifier),
      resolve(parent, args) {
        return fetch(
          "https://api.gateway.attomdata.com/propertyapi/v1.0.0/property/address?postalcode=95076&page=1&pagesize=100",
          {
            headers: {
              Accept: "application/json",
              APIKey: "XXXXXXXXXXXXXXXXXXXX"
            }
          }
        )
          .then((response) => { 
            const jsonResponse = response.json();
            return jsonResponse
          }).then((jsonResonse) => console.log(JSON.stringify(jsonResonse)))
          .then(res => res.data)
          .catch(error => {
            console.log(error);
          });
      }
    }
  }
});

module.exports = new GraphQLSchema({
  query: RootQuery
});

Im running it on a express server and do my checks on localhost:5000/graphql

---

在评论中，我们得出以下结论：

连接地址类型和根查询类型需要另一种类型。我们可以引入查询类型，调整查询类型的返回类型：

type Property {
  id: Identifier
  address: Address
}

type Query {
  property: [Property] # consider using plural field name "properties"
}

---

我创建了一个工作的Codesandboy来显示它的行为。

请显示所有相关的代码，包括您尝试过的代码，以及您遇到的错误或意外行为。在我看来，您似乎缺少

地址

和查询字段之间的类型。您将引入

类型属性{id:Identifier，address:address}

。然后，您的属性查询将返回该属性的数组@赫尔库，谢谢你，伙计，就是这样！！如果你不介意的话，我会补充一个答案