Graphql 猫鼬不喜欢的图形';不能执行类似的查询
我很高兴发现graphql compose,并开始在projet中使用它。实际上,我在查询比教程中提到的更复杂的查询时遇到了一个问题。例如,我想对mongoose表执行一个like查询。如果我将教程示例修改为使用名称进行过滤,则一切正常Graphql 猫鼬不喜欢的图形';不能执行类似的查询,graphql,Graphql,我很高兴发现graphql compose,并开始在projet中使用它。实际上,我在查询比教程中提到的更复杂的查询时遇到了一个问题。例如,我想对mongoose表执行一个like查询。如果我将教程示例修改为使用名称进行过滤,则一切正常 { userMany(filter: { name: "MICHA" }, limit: 5, sort: _ID_ASC) { name languages { language skill } co
{
userMany(filter: { name: "MICHA" }, limit: 5, sort: _ID_ASC) {
name
languages {
language
skill
}
contacts {
email
}
gender
age
}
}
但是,如果我试图使用正则表达式,我会立即陷入我的查询所在的位置
{
userMany(filter: { name: "/MICH/i" }, limit: 5, sort: _ID_ASC) {
name
languages {
language
skill
}
contacts {
email
}
gender
age
}
}
p、 s:很抱歉,我不得不使用graphql标记而不是graphql compose,因为后者仍然不存在,而且我没有足够的积分来创建它:-(我找到了上面评论中提到的解决方案:
import { composeWithMongoose } from 'graphql-compose-mongoose';
import { composeWithRelay } from 'graphql-compose-relay';
import { schemaComposer } from 'graphql-compose';
const Entity = require ('../db/entity').default
const customizationOptions = {}; // left it empty for simplicity, described below
const EntityTC = composeWithRelay(composeWithMongoose(Entity, customizationOptions));
//export const ProductTC = composeWithRelay(composeWithMongoose(Product));
//TODO make this function evolve to allow filtering on a specified field in params
//Found in https://github.com/graphql-compose/graphql-compose-examples/blob/master/examples/northwind/models/product.js#L38,L49
const addEntityNameRegexpSearch = function () {
const extendedResolver = EntityTC.getResolver('findMany').addFilterArg({
name: 'nameRegexp',
type: 'String',
description: 'Search by name in regExp',
query: (query, value, resolveParams) => { // eslint-disable-line
query.name = new RegExp(value, 'i'); // eslint-disable-line
},
});
extendedResolver.name = 'findMany';
EntityTC.addResolver(extendedResolver);
};
addEntityNameRegexpSearch()
schemaComposer.rootQuery().addFields({
entityById: EntityTC.getResolver('findById'),
entityByIds: EntityTC.getResolver('findByIds'),
entityOne: EntityTC.getResolver('findOne'),
entityMany: EntityTC.getResolver('findMany'),
entityCount: EntityTC.getResolver('count'),
entityConnection: EntityTC.getResolver('connection'),
entityPagination: EntityTC.getResolver('pagination'),
});
schemaComposer.rootMutation().addFields({
entityCreate: EntityTC.getResolver('createOne'),
entityUpdateById: EntityTC.getResolver('updateById'),
entityUpdateOne: EntityTC.getResolver('updateOne'),
entityUpdateMany: EntityTC.getResolver('updateMany'),
entityRemoveById: EntityTC.getResolver('removeById'),
entityRemoveOne: EntityTC.getResolver('removeOne'),
entityRemoveMany: EntityTC.getResolver('removeMany'),
});
const graphqlSchema = schemaComposer.buildSchema();
export default graphqlSchema;
我修改了查询以对应于方法参数:
const queries = {
SHOP_LIST: gql `
query entityMany($name: String!){
entityMany(filter: { nameRegexp: $name }, limit: 3){name}
}
`
}
我用同样的方法:
<Query query={queries.SHOP_LIST} variables={{name:this.state.name}}>
我发现这个链接稍微谈到了这个问题。这个链接可能是解决方案:您是用实际的findById函数替换“findById”,还是已经内置了?例如entityById:EntityTC.getResolver('findById')我正在使用内置函数