如何在GraphQL中变异关系字段？

假设你有两种类型的玩家技能

type PlayerSkills {
  playerID: Player
  health: Int
  attack: Int
  defence: Int
}

type Player {
  playerID: ID!
  playerName: String
  balance: Int
  playerSkills: PlayerSkills
  inventory: [Item]
}

如果您创建一个变种来添加一个新玩家，您将如何告诉GraphQL一个特定的玩家与一个特定的技能集合相关联

mutation (
  $playerID: ID!, 
  $playerName: String, 
  $balance: Int
  $playerSkills: PlayerPlayerSkillsRelation

) {
  createPlayer(data: {
    playerID: $playerID, 
    playerName: $playerName, 
    balance: $balance,
    playerSkills: $playerSkills
  }) {
    playerID
    playerName
    balance
    playerSkills {
      playerID
    }
  }
}

---

我认为你把输入部分复杂化了。通常，当您的突变操作与您的查询相同的数据时，它们即使不完全相同，也会非常相似。除非有其他要求，我会这样安排：

mutation (
  $playerID: ID!, 
  $playerName: String, 
  $balance: Int
  $playerSkills: PlayerSkillsInput
) {
  createPlayer(data: {
    playerID: $playerID, 
    playerName: $playerName, 
    balance: $balance,
    playerSkills: $playerSkills
  }) {
    playerID
    playerName
    balance
    playerSkills {
      playerID
    }
  }
}

input PlayerSkillsInput {
  health: Int
  attack: Int
  defence: Int
}

请注意，

PlayerSkillsInput

中既没有

playerSkillsRelation

，也没有字段

playerID

。输入玩家只需要掌握自己的技能，而与玩家无关，因为您可以在实现代码中自己推断出这一点。只有被创建的玩家才能拥有这些技能，所以你不需要额外的输入字段

不能完全确定

connect

和

disconnect

，但如果需要，可以轻松地将它们添加到

PlayerSkillsInput

mutation (
  $playerID: ID!, 
  $playerName: String, 
  $balance: Int
  $playerSkills: PlayerSkillsInput
) {
  createPlayer(data: {
    playerID: $playerID, 
    playerName: $playerName, 
    balance: $balance,
    playerSkills: $playerSkills
  }) {
    playerID
    playerName
    balance
    playerSkills {
      playerID
    }
  }
}

input PlayerSkillsInput {
  health: Int
  attack: Int
  defence: Int
}