交换GraphViz图（DOT）中两个节点的位置

我使用

DOT

语言在

R

中创建一个图表。当我得到一个奇怪的结果时，我对如何交换两个节点的位置感兴趣：节点8和节点c4

守则：

digraph DAG {
    # Initialization of node attributes
    node [shape = box, color = blue]; 2; 3; 4; 

    # Revision to node attributes
    { node [shape = box,style = filled,fillcolor = yellow];  8}

    # Revision to node attributes
    { node [shape = diamond, color = "red"];  c1; c2; c3; c4}

    { rank=same; c1; c2; c3}
    { rank=same; 8; c4}

    # Initialization of edge attributes
    edge [color = green, rel = yields]

    # Edge statements
    2->c1 [headport = w]; 
    c1->c2->c3 
    c2->c1 [tailport = n, headport = n];

    8->c3  [tailport = n, headport = s];
    c3->3  [tailport = e, headport = n]; 
    c3->c2 [tailport = n, headport = n];

    3->c4  [tailport = s, headport = n];
    c4->4  [tailport = s, headport = n];
    c4->8  [tailport = w, headport = e];
}

结果（不正确）为：

对于“错误方向”边缘，您可以

• 交换节点并使用属性

  dir=back

  反转其“力”
• 使用属性

  constraint=none

  禁用其“强制”

在你的情况下，你可以代替

8->c4  [tailport = e, headport = w, dir = back];

8->c4  [tailport = e, headport = w, dir = back];

由任何一方

c4->8  [tailport = w, headport = e, constraint = none];

或者

对于“错误的方式”边缘，您可以

• 交换节点并使用属性

  dir=back

  反转其“力”
• 使用属性

  constraint=none

  禁用其“强制”

在你的情况下，你可以代替

8->c4  [tailport = e, headport = w, dir = back];

8->c4  [tailport = e, headport = w, dir = back];

由任何一方

c4->8  [tailport = w, headport = e, constraint = none];

或者