Hibernate：如何在HQL中使用数组到字符串（ARRAY（））

POITable

@Entity
@Table(name="User")
public class User implements Serializable{
    private String username; //Key

    // Getters and setters
}    

@Entity
@Table(name="POITable")
public class POI implements Serializable{
    private Integer id; //Key
    private String name;

    // Getters and setters
}

@Entity
@Table(name="VisitedPlaceTable")
public class VisitedPlace implements Serializable{
    private Integer id; //Key
    private User user; //Many TO One relation
    private POI poi; //Many TO One relation

    // Getters and setters
}

===================
| id |    name    |
ــــــــــــ+ـــــ+
| 1  | poi name 1 |
-----+------------+
| 2  | poi name 2 |
===================

访问位置表

@Entity
@Table(name="User")
public class User implements Serializable{
    private String username; //Key

    // Getters and setters
}    

@Entity
@Table(name="POITable")
public class POI implements Serializable{
    private Integer id; //Key
    private String name;

    // Getters and setters
}

@Entity
@Table(name="VisitedPlaceTable")
public class VisitedPlace implements Serializable{
    private Integer id; //Key
    private User user; //Many TO One relation
    private POI poi; //Many TO One relation

    // Getters and setters
}

===================
| id |    name    |
ــــــــــــ+ـــــ+
| 1  | poi name 1 |
-----+------------+
| 2  | poi name 2 |
===================

这是本机查询

=================================
| id |  user_username  | poi_id |
ــــــــ+ـــــــــــــــــ+ـــــ+
| 3  | xxxx@gmail.com  |   1    |
-----+-----------------+--------+
| 4  | xxxx@gmail.com  |   2    |
=================================

返回下一个结果（TRUE和预期结果：））

"xxxx@gmail.com“，“1 | 2”

但在HQL中

SELECT CONCAT('"',model.user_username,'","',**ARRAY_TO_STRING(ARRAY(SELECT DISTINCT visitedPlace.poi_id FROM VisitedPlaceTable visitedPlace WHERE visitedPlace.user_username = model.user_username),'|')**,'"','') FROM TourismPOIVisited model  INNER join POITable poi on poi.id = model.poi_id WHERE model.user_username='xxxx@gmail.com' GROUP BY model.user_username

它开火了

第1:70行：意外标记：选择

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那么，如何在HQL中使用ARRAY\u TO\u STRING（ARRAY（））或任何其他等效函数来实现这一点呢？

HQL查询是针对对象模型编写的，而不是针对数据库架构。因此，发布您的Pojo和主类，以便我们能够help@Akshay对象模型（实体是问题主体中的第一件事）请仔细阅读我的问题，无论如何，我都添加了（模型和模式）以使问题更清楚：）