JPQL/HQL和JPA/Hibernate:select构造函数表达式中的布尔表达式不工作(意外的AST节点:and、NPE、HqlSqlWalker.setAlias)?
我有一个JPQL声明来返回体育比赛时间表:JPQL/HQL和JPA/Hibernate:select构造函数表达式中的布尔表达式不工作(意外的AST节点:and、NPE、HqlSqlWalker.setAlias)?,hibernate,jpa,hql,jpql,boolean-expression,Hibernate,Jpa,Hql,Jpql,Boolean Expression,我有一个JPQL声明来返回体育比赛时间表: SELECT NEW com.kawoolutions.bbstats.view.ScheduleGameLine( ga.id AS gid , ga.scheduledTipoff
SELECT NEW com.kawoolutions.bbstats.view.ScheduleGameLine(
ga.id AS gid
, ga.scheduledTipoff AS scheduledtipoff
...
, sch.finalScore AS homefinalscore
, sca.finalScore AS awayfinalscore
, sch.finalScore IS NOT NULL AND sca.finalScore IS NOT NULL AS hasfinalscore
)
我希望最后一个表达式(布尔值)计算为布尔值,以指示是否已完全报告了游戏的最终分数(两个类型为score的实体,这里是sch和sca,用于主客场分数)。但是,Hibernate失败,出现异常:
11.02.2011 18:40:16 org.hibernate.hql.ast.ErrorCounter reportError
SCHWERWIEGEND: <AST>:17:32: unexpected AST node: AND
Exception in thread "main" java.lang.NullPointerException
at org.hibernate.hql.ast.HqlSqlWalker.setAlias(HqlSqlWalker.java:1000)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.aliasedSelectExpr(HqlSqlBaseWalker.java:2381)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.constructor(HqlSqlBaseWalker.java:2505)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectExpr(HqlSqlBaseWalker.java:2256)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectExprList(HqlSqlBaseWalker.java:2121)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectClause(HqlSqlBaseWalker.java:1522)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:593)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:301)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:244)
at org.hibernate.hql.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:254)
at org.hibernate.hql.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:185)
at org.hibernate.hql.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:136)
at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:101)
at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:80)
at org.hibernate.engine.query.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:124)
at org.hibernate.impl.AbstractSessionImpl.getHQLQueryPlan(AbstractSessionImpl.java:156)
at org.hibernate.impl.AbstractSessionImpl.createQuery(AbstractSessionImpl.java:135)
at org.hibernate.impl.SessionImpl.createQuery(SessionImpl.java:1770)
at org.hibernate.ejb.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:272)
at com.kawoolutions.bbstats.Main.executeJpqlStatement(Main.java:167)
at com.kawoolutions.bbstats.Main.main(Main.java:154)
我真的很想知道为什么这不适用于一个案例。这里怎么了?是我吗?是JPA吗?是冬眠吗?Bug?它看起来像是一种特定的行为。JPA根本不允许在
SELECT
子句中使用条件表达式,尽管它允许CASE
表达式
以下是来自以下网站的JPQL语法的相关部分:
选择_表达式::=
单值路径表达式|
标量表达式|
聚合表达式|
识别变量|
对象(标识_变量)|
构造器表达式
构造函数\u表达式::=
新构造函数名称(构造函数项{,构造函数项}*)
构造函数\u项::=
单值路径表达式|
标量表达式|
聚合表达式|
识别变量
标量表达式::=
简单算术表达式|
字符串_主|
枚举主|
主要日期时间|
布尔_主|
case_表达式|
实体类型表达式什么是布尔型表达式?引用的布尔成员(它们确实有效)?@Kawu:它是布尔文本(
TRUE
或FALSE
),输入参数和布尔属性。
SELECT NEW com.kawoolutions.bbstats.view.ScheduleGameLine(
ga.id AS gid
, ga.scheduledTipoff AS scheduledtipoff
...
, sch.finalScore AS homefinalscore
, sca.finalScore AS awayfinalscore
, CASE WHEN sch.finalScore IS NOT NULL AND sca.finalScore IS NOT NULL THEN TRUE ELSE FALSE END AS hasfinalscore
)
select_expression ::=
single_valued_path_expression |
scalar_expression |
aggregate_expression |
identification_variable |
OBJECT(identification_variable) |
constructor_expression
constructor_expression ::=
NEW constructor_name ( constructor_item {, constructor_item}* )
constructor_item ::=
single_valued_path_expression |
scalar_expression |
aggregate_expression |
identification_variable
scalar_expression ::=
simple_arithmetic_expression |
string_primary |
enum_primary |
datetime_primary |
boolean_primary |
case_expression |
entity_type_expression