Hibernate JPA count query可按查询对组的总结果行进行计数
如何在JPQL中获取SQL查询下面的总结果行:Hibernate JPA count query可按查询对组的总结果行进行计数,hibernate,jpa,hql,Hibernate,Jpa,Hql,如何在JPQL中获取SQL查询下面的总结果行: select count(usertransa0_.id) as col_0_0_ from user_transaction usertransa0_ cross join merchant_master merchantma1_ where usertransa0_.merchant_master=merchantma1_.id an
select
count(usertransa0_.id) as col_0_0_
from
user_transaction usertransa0_ cross
join
merchant_master merchantma1_
where
usertransa0_.merchant_master=merchantma1_.id
and usertransa0_.status=0
and (
usertransa0_.transaction_date between '2015-02-19' and '2015-02-20'
)
group by
merchantma1_.full_name;
我试过:
SELECT COUNT(ut)
FROM UserTransaction ut
WHERE ut.status = :stus AND ut.transactionDate between :frm AND :toDt"
GROUP BY ut.merchantMaster.fullName
但它只返回第一行计数,如何才能得到总行数
编辑:
我的实体看起来像:
public class UserTransaction extends BaseEntity {
@OneToOne(fetch = FetchType.LAZY)
private UserInfo info;
@OneToOne(fetch = FetchType.LAZY)
private MerchantMaster merchantMaster;
@OneToOne(fetch = FetchType.LAZY)
private PaymentMaster paymentMaster;
@Column(name = "AMOUNT")
private BigDecimal amount;
@Temporal(TemporalType.TIMESTAMP)
@Column(name = "TRANSACTION_DATE")
private Date transactionDate;
@Column(name = "STATUS")
private Integer status;
private String userTransactionID;
@OneToOne(cascade = { CascadeType.ALL }, fetch = FetchType.LAZY)
private UserTransactionRequest trRequest;
@OneToOne(cascade = { CascadeType.ALL }, fetch = FetchType.LAZY)
private UserTransactionResponse trResponse;
//getters & setters
}
您的查询将返回一个Long数组。每个Long是给定MerchantMaster名称的
UserTransaction
计数
如果在NamedQuery中有查询,则可以使用(如果没有,则可以使用creatiyQuery()
方法并使用JPQL查询字符串):
现在,查询将返回一个对象数组,第一个对象是count,第二个对象是name。您还需要修改代码以获得结果:
TypedQuery<Object[]> query = em.createNamedQuery("UserTransaction.MyQuery", Object[].class);
List<Object []> results = query.getResultList();
for (Object [] row : results) {
Long count = (Long) row[0];
String name = (String) row[1];
}
TypedQuery query=em.createNamedQuery(“UserTransaction.MyQuery”,Object[].class);
List results=query.getResultList();
对于(对象[]行:结果){
长计数=(长)行[0];
字符串名称=(字符串)行[1];
}
UserTransaction和MerchantMaster之间的关系是什么,@OneToMany
?。您可以发布您的实体代码吗?@DavidSN no,@OneToOne
relationship为任何JPQL查询生成的SQL都将显示在日志中,这样您就可以计算出需要什么,您希望得到什么结果?如果要获取UserTransaction的总计数,可以从JPQL查询中删除group by
。此时,您的查询返回每个MerchantMaster的UserTransaction计数name@DavidSN我需要每个MerchantMaster名称的总计数。+1作为答案,但我需要分页结果,在分页中我必须找到按函数分组返回的结果总数。@Rembo我不确定这是否是您的意思,但是如果你想知道组的总数。您可以使用query.getResultList().size()
SELECT COUNT(ut), ut.merchantMaster.fullName
FROM UserTransaction ut
WHERE ut.status = :stus AND ut.transactionDate between :frm AND :toDt"
GROUP BY ut.merchantMaster.fullName
TypedQuery<Object[]> query = em.createNamedQuery("UserTransaction.MyQuery", Object[].class);
List<Object []> results = query.getResultList();
for (Object [] row : results) {
Long count = (Long) row[0];
String name = (String) row[1];
}