Hibernate @如何使Json引用现有的外键?
我正在制作一个Spring Boot RESTful应用程序。我有两个实体:访客:Hibernate @如何使Json引用现有的外键?,hibernate,rest,spring-data-jpa,spring-rest,Hibernate,Rest,Spring Data Jpa,Spring Rest,我正在制作一个Spring Boot RESTful应用程序。我有两个实体:访客: @Data @NoArgsConstructor @AllArgsConstructor @Entity public class Customer { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private int id; private String name; private String em
@Data
@NoArgsConstructor
@AllArgsConstructor
@Entity
public class Customer {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private int id;
private String name;
private String email;
private String gender;
}
及产品
@Data
@AllArgsConstructor
@NoArgsConstructor
@Entity
public class Product {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private int id;
private String name;
private int qty;
private int price;
@ManyToOne(cascade = CascadeType.ALL)
@JoinColumn(name = "customer_id", referencedColumnName = "id")
private Customer customer;
}
这就是我试图通过控制器将Json推入OrderRequest对象的方式:
@PostMapping("/placeOrder")
public Product saveOrder(@RequestBody OrderRequest request){
return productRepository.save(request.getProduct());
}
OrderRequest类:
@Data
@AllArgsConstructor
@NoArgsConstructor
public class OrderRequest {
private Product product;
}
存储库类是标准的:
public interface ProductRepository extends JpaRepository<Product, Integer> {}
public interface CustomerRepository extends JpaRepository<Customer, Integer> {}
问题:如何使客户表中已有一行,我可以向服务器发送Json,在其中,我只指出了产品参数和一个外键参数,该参数将作为对客户行的引用???谢谢在控制器层中公开持久性级别实体不是最佳做法,因为API与数据的内部表示相耦合 实现需求的常用方法是使用Transfer对象模式。也就是说,创建单独的类以在API中使用。在您的用例中,您可以创建具有以下结构的ProductTO类:
public class ProductTO {
private int id;
private String name;
private int qty;
private int price;
private int customerId;
}
然后,您可以手动在ProductTO和Product之间映射字段,或者使用任何映射库(例如:MapStruct)自动复制两个类中同名字段的值
外键应手动分配:
Customer customer = this.customerRepo.findById(productTO.getCustomerId()).orElseThrow(() -> new YourException());
product.setCustomer(customer);
如何使用mapstruct实现此功能@萨蒂亚戈
Customer customer = this.customerRepo.findById(productTO.getCustomerId()).orElseThrow(() -> new YourException());
product.setCustomer(customer);