Hibernate org.Hibernate.exception.sqlgrammareexception
我正在使用Hibernate和Struts2创建登录页面。在下面的代码中,我试图从LoginTable获取数据,其中用户名和密码是两个动态变量Hibernate org.Hibernate.exception.sqlgrammareexception,hibernate,Hibernate,我正在使用Hibernate和Struts2创建登录页面。在下面的代码中,我试图从LoginTable获取数据,其中用户名和密码是两个动态变量 String hql = "from LoginTable as log where log.userId=:userName and log.password=:passw"; Query query = session.createQuery(hql); query.setStrin
String hql = "from LoginTable as log where log.userId=:userName and log.password=:passw";
Query query = session.createQuery(hql);
query.setString("userName", userName);
query.setString("passw", passw);
List result = query.list();
登录代码:
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import javax.persistence.Table;
@Entity
@Table(name="user_details")
public class LoginTable {
@Id
@GeneratedValue
private int id;
@Column(name="user_id")
private String userId;
@Column(name="password")
private String password;
@Column(name="user_nm")
private String userName;
@Column(name="designation")
private String designation;
@Column(name="email")
private String email;
@Column(name="mobile")
private String mobile;
@Column(name="user_privilege")
private String userPriviledge;
@Column(name="first_login")
private String firstLogin;
@Column(name="password_status")
private String passwordStatus;
public String getUserId() {
return userId;
}
public void setUserId(String userId) {
this.userId = userId;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public String getUserName() {
return userName;
}
public void setUserName(String userName) {
this.userName = userName;
}
public String getDesignation() {
return designation;
}
public void setDesignation(String designation) {
this.designation = designation;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
public String getMobile() {
return mobile;
}
public void setMobile(String mobile) {
this.mobile = mobile;
}
public String getUserPriviledge() {
return userPriviledge;
}
public void setUserPriviledge(String userPriviledge) {
this.userPriviledge = userPriviledge;
}
public String getFirstLogin() {
return firstLogin;
}
public void setFirstLogin(String firstLogin) {
this.firstLogin = firstLogin;
}
public String getPasswordStatus() {
return passwordStatus;
}
public void setPasswordStatus(String passwordStatus) {
this.passwordStatus = passwordStatus;
}
}
但是在执行了上面的代码之后,我得到了下面的异常。
org.hibernate.exception.sqlgrammareexception:无法执行查询
只有我得到的SQLGrammarException 这个查询没有错。张贴完整的stacktrace以识别问题。同时分享登录类的代码。请发布完整的stacktrace。谢谢您的帮助。我得到了确切的问题。现在我可以解决这个问题了。