Hibernate Criteria API：我可以使用单向多人关联的条件吗？

我有

用户

实体：

@Entity
@Table(name = "users")
public class User implements Serializable{

    @Id
    @GeneratedValue
    private Long id;
    @Column(nullable = false)
    private String name;

和

项目

实体，该实体与

用户

有单向的

多个

关联：

@Entity
@Table(name = "projects")
public class Project {
    @Id
    @GeneratedValue
    private Long id;

    @Column
    private String name;

    @ManyToMany(cascade = CascadeType.ALL)
    @JoinTable
    private List<User> users;

但它仍然“需要”

Project

在

User

实体中进行关联。如果有人决定帮助我，我会很高兴的——提前谢谢你抽出时间。 更新：我可能找到了可行但不优雅的解决方案，但我仍然向您寻求帮助解决方案：

---

我还尝试了以下方法：

@Override
public List<User> getByProjectId(Long projectId) {
    Criteria criteria = createCriteria(User.class);
    criteria.setFetchMode("project", FetchMode.JOIN);
    criteria.add(Restrictions.eq("project.id", projectId));
    criteria.setResultTransformer(CriteriaSpecification.DISTINCT_ROOT_ENTITY);
    List<User> users = (List<User>) criteria.list();
    return users;
}

public List<User> getByProjectId(Long projectId) {
    Query query = getCurrentSession().createQuery("from User as user right 
        join Project project where project.id=:projectId");
    query.setLong("projectId", projectId);
    List users = query.list();
    return users;
}

public List<User> getByProjectId(Long projectId) {
    Query query = getCurrentSession().createQuery("from User as user right 
        join Project project where project.id=:projectId");
    query.setLong("projectId", projectId);
    List users = query.list();
    return users;
}

---

看起来还行，但如果你们中的一些人能以更优雅的方式来解决我的问题，我还是会很高兴的——提前感谢所有观众。

我还尝试了以下方法：

@Override
public List<User> getByProjectId(Long projectId) {
    Criteria criteria = createCriteria(User.class);
    criteria.setFetchMode("project", FetchMode.JOIN);
    criteria.add(Restrictions.eq("project.id", projectId));
    criteria.setResultTransformer(CriteriaSpecification.DISTINCT_ROOT_ENTITY);
    List<User> users = (List<User>) criteria.list();
    return users;
}

public List<User> getByProjectId(Long projectId) {
    Query query = getCurrentSession().createQuery("from User as user right 
        join Project project where project.id=:projectId");
    query.setLong("projectId", projectId);
    List users = query.list();
    return users;
}

public List<User> getByProjectId(Long projectId) {
    Query query = getCurrentSession().createQuery("from User as user right 
        join Project project where project.id=:projectId");
    query.setLong("projectId", projectId);
    List users = query.list();
    return users;
}