Hive 直线查询输出采用JSON格式，而不是csv表

我使用下面这样的直线查询，HDFS中的底层数据来自大型机服务器。我只想执行一个查询并将其转储为csv（或任何表格格式）：

我的问题是：

The format is not clean, there are extra rows at top and bottom ;
It appears as JSOn and not a table.
Some numbers seem hexadecimal    format.

+-----------------------------------------------------------------------------------------------------------------------------+
|  col1:{"col1_a":"00000"   col1_b:"0"  col1_c:{"col11_a":"00000"   col11_tb:{"mo_acct_tp":"0"  col11_c:"0"}}   col1_d:"0"}|  
+-----------------------------------------------------------------------------------------------------------------------------+

---

我想要一个顶部有列名且没有嵌套的常规csv。

您必须执行

showHeader=true

，您将获得所需的结果

beeline -u 'jdbc:hive2://server.com:port/;serviceDiscoveryMode=zooKeeper;zooKeeperNamespace=hiveserver2;transportMode=binary' -–showHeader=true --outputformat=csv2 -e "SELECT * FROM tbl LIMIT 2;"> tables1.csv

您也可以尝试表格格式，

outputformat=table

，这不会将csv作为输出，但会提供一个干净的表格结构，如下所示：

+-----+---------+-----------------+
| id  |  value  |     comment     |
+-----+---------+-----------------+
| 1   | Value1  | Test comment 1  |
| 2   | Value2  | Test comment 2  |
| 3   | Value3  | Test comment 3  |
+-----+---------+-----------------+

---

请帮助我们更好地了解您的数据

在直线或配置单元中运行select查询时，您的表是否具有如下数据：

> select * from test;
+------------------------------------------------------------------------------------------------------------------------+--+
|                                                        test.col                                                        |
+------------------------------------------------------------------------------------------------------------------------+--+
| {"col1_a":"00000","col1_b":"0","col1_c":{"col11_a":"00000","col11_tb":{"mo_acct_tp":"0","col11_c":"0"}},"col1_d":"0"}  |
+------------------------------------------------------------------------------------------------------------------------+--+

如果是，您可能必须解析Json对象中的数据，如下所示：

select
get_json_object(tbl.col, '$.col1_a') col1_a
, get_json_object(tbl.col, '$.col1_b') col1_b
, get_json_object(tbl.col, '$.col1_c.col11_a') col1_c_col11_a 
, get_json_object(tbl.col, '$.col1_c.col11_tb.col11_c') col1_c_col11_tb_col11_c
, get_json_object(tbl.col, '$.col1_c.col11_tb.mo_acct_tp') col1_c_col11_tb_mo_acct_tp
, get_json_object(tbl.col, '$.col1_d') col1_d
from test tbl
INFO  : Completed executing command(queryId=hive_20180918182457_a2d6230d-28bc-4839-a1b5-0ac63c7779a5); Time taken: 1.007 seconds
INFO  : OK
+---------+---------+-----------------+--------------------------+-----------------------------+---------+--+
| col1_a  | col1_b  | col1_c_col11_a  | col1_c_col11_tb_col11_c  | col1_c_col11_tb_mo_acct_tp  | col1_d  |
+---------+---------+-----------------+--------------------------+-----------------------------+---------+--+
| 00000   | 0       | 00000           | 0                        | 0                           | 0       |
+---------+---------+-----------------+--------------------------+-----------------------------+---------+--+
1 row selected (2.058 seconds)

然后可以在命令行中使用此查询将结果导出到文件中

>beeline -u 'jdbc:hive2://server.com:port/;serviceDiscoveryMode=zooKeeper;zooKeeperNamespace=hiveserver2;transportMode=binary' --showHeader=false --outputformat=csv2 -e "select
get_json_object(tbl.col, '$.col1_a') col1_a
, get_json_object(tbl.col, '$.col1_b') col1_b
, get_json_object(tbl.col, '$.col1_c.col11_a') col1_c_col11_a 
, get_json_object(tbl.col, '$.col1_c.col11_tb.col11_c') col1_c_col11_tb_col11_c
, get_json_object(tbl.col, '$.col1_c.col11_tb.mo_acct_tp') col1_c_col11_tb_mo_acct_tp
, get_json_object(tbl.col, '$.col1_d') col1_d
from corpde_commops.test tbl;" > test.csv

如果需要文件中的列名，请将--showHeader=true

最终产出将是：

>cat test.csv 
col1_a,col1_b,col1_c_col11_a,col1_c_col11_tb_col11_c,col1_c_col11_tb_mo_acct_tp,col1_d
00000,0,00000,0,0,0

很明显，我看不出你的直截了当的陈述有任何错误。

如果您的数据与上面的示例不同，则解决方案可能是另一种方式

---

祝你一切顺利

outputformat=table不会将嵌套的JSON转换为表。谢谢你。

>cat test.csv 
col1_a,col1_b,col1_c_col11_a,col1_c_col11_tb_col11_c,col1_c_col11_tb_mo_acct_tp,col1_d
00000,0,00000,0,0,0