Ios 使用SLRequest在tweet中发布图像-图像未显示

Ios 使用SLRequest在tweet中发布图像-图像未显示,ios,twitter,uiimage,slrequest,Ios,Twitter,Uiimage,Slrequest,我正在尝试使用SLRequest以编程方式将图像(从iOS设备)上载到用户的twitter帐户。推文文本上传到推文中,但图像从未出现。响应状态代码为200 显然,基本功能正常,否则tweet将根本不会显示在用户流中,我已经检查了图像是否找到,以及(NSData)变量是否包含预期的字节数 查看下面的代码-正如您从注释代码中看到的,我尝试了各种不同的修改,但没有成功。。。感谢您的任何想法/帮助 - (void) postToTwitter:(NSString *)postMessage withIm

我正在尝试使用SLRequest以编程方式将图像(从iOS设备)上载到用户的twitter帐户。推文文本上传到推文中,但图像从未出现。响应状态代码为200

显然,基本功能正常,否则tweet将根本不会显示在用户流中,我已经检查了图像是否找到,以及(NSData)变量是否包含预期的字节数

查看下面的代码-正如您从注释代码中看到的,我尝试了各种不同的修改,但没有成功。。。感谢您的任何想法/帮助

- (void) postToTwitter:(NSString *)postMessage withImageNamed:(NSString *)imageName {

    // Get Twitter account
    ACAccountStore *smAccount = [[ACAccountStore alloc] init];
    ACAccountType *smType = [smAccount accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierTwitter];

    NSDictionary *postOptions = nil;

    // Attempt to post the postMessage
    [smAccount requestAccessToAccountsWithType:smType options:postOptions completion:^(BOOL accessGranted, NSError *error) {

        // Access code block

        if (accessGranted) {

            NSLog(@"Access permitted");

            NSArray *smAccountList = [smAccount accountsWithAccountType:smType];

            if ([smAccountList count] > 0) {

                // Get the first Twitter account
                ACAccount *postingAccount = [smAccountList lastObject];

                // Create the post request
                //SLRequest *postRequest = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodPOST URL:[NSURL URLWithString:@"https://api.twitter.com/1.1/statuses/update.json"] parameters:[NSDictionary dictionaryWithObject:postMessage forKey:@"status"]];
                //SLRequest *postRequest = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodPOST URL:[NSURL URLWithString:@"https://upload.twitter.com/1.1/media/upload.json"] parameters:nil];
                SLRequest *postRequest = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodPOST URL:[NSURL URLWithString:@"https://api.twitter.com/1.1/statuses/update.json"] parameters:nil];

                // Add image to post
                // TODO - Check which to use >
                UIImage *postImage = [UIImage imageNamed:imageName];
                //UIImage *postImage = [UIImage imageWithContentsOfFile:imageName];
                //NSData *imageData = UIImageJPEGRepresentation (postImage, 0.5f); // Set compression

                NSData *imageData = UIImagePNGRepresentation(postImage);

                //[postRequest addMultipartData:imageData withName:@"media" type:@"image/png" filename:@"image.png"];
                [postRequest addMultipartData:imageData withName:@"media[]" type:@"multipart/form-data" filename:@"image.png"];

                // Add text
                [postRequest addMultipartData:[postMessage dataUsingEncoding:NSUTF8StringEncoding] withName:@"status" type:@"multipart/form-data" filename:nil];

                // Execute the post
                [postRequest setAccount:postingAccount];
                [postRequest performRequestWithHandler:^(NSData *responseData, NSHTTPURLResponse *urlResponse, NSError *error) {

                    // Post code block
                    if (error) {

                        NSLog(@"Post failed - %@", error);

                        if (_delegate && [_delegate respondsToSelector:@selector(didNotPost:)])
                            [_delegate didNotPost:self];
                    } else {

                        NSLog(@"Post complete");

                        if (_delegate && [_delegate respondsToSelector:@selector(didPost:)])
                            [_delegate didPost:self];
                    }
                }];
            }
        } else {

            NSLog(@"Access denied - %@", error);

            if (_delegate && [_delegate respondsToSelector:@selector(didNotPost:)])
                [_delegate didNotPost:self];
        }


    } ];
}
以下是回应:

(lldb) po urlResponse
<NSHTTPURLResponse: 0x7fb9bf80> { URL: https://api.twitter.com/1.1/statuses/update.json } { status code: 200, headers {
    "Cache-Control" = "no-cache, no-store, must-revalidate, pre-check=0, post-check=0";
    "Content-Disposition" = "attachment; filename=json.json";
    "Content-Encoding" = gzip;
    "Content-Length" = 751;
    "Content-Type" = "application/json;charset=utf-8";
    Date = "Thu, 02 Apr 2015 17:14:20 GMT";
    Expires = "Tue, 31 Mar 1981 05:00:00 GMT";
    "Last-Modified" = "Thu, 02 Apr 2015 17:14:20 GMT";
    Pragma = "no-cache";
    Server = "tsa_b";
    "Set-Cookie" = "lang=en";
    Status = "200 OK";
    "Strict-Transport-Security" = "max-age=631138519";
    "x-access-level" = "read-write";
    "x-connection-hash" = 6f61f3c96ba990931cca3fa950a42b38;
    "x-content-type-options" = nosniff;
    "x-frame-options" = SAMEORIGIN;
    "x-response-time" = 51;
    "x-transaction" = b2c77803db7e996d;
    "x-tsa-request-body-time" = 426;
    "x-twitter-response-tags" = BouncerCompliant;
    "x-xss-protection" = "1; mode=block";
} }
(lldb)po URL响应
{URL:https://api.twitter.com/1.1/statuses/update.json }{状态代码:200,标题{
“缓存控制”=“无缓存,无存储,必须重新验证,预检查=0,后检查=0”;
“内容处置”=“附件;文件名=json.json”;
“内容编码”=gzip;
“内容长度”=751;
“内容类型”=“应用程序/json;字符集=utf-8”;
日期=“2015年4月2日星期四17:14:20 GMT”;
Expires=“1981年3月31日星期二05:00:00 GMT”;
“上次修改”=“2015年4月2日星期四17:14:20 GMT”;
Pragma=“无缓存”;
Server=“tsa_b”;
“设置Cookie”=“lang=en”;
Status=“200正常”;
“严格的交通安全”=“最大年龄=631138519”;
“x访问级别”=“读写”;
“x-connection-hash”=6f61f3c96ba990931cca3fa950a42b38;
“x-content-type-options”=nosniff;
“x-frame-options”=SAMEORIGIN;
“x响应时间”=51;
“x交易”=B2C77803B7E996D;
“x-tsa-request-body-time”=426;
“x-twitter-response-tags”=BouncerCompliant;
“x-xss-protection”=“1;模式=块”;
} }

所以在经历了很多痛苦之后,我意识到我发布到了错误的twitter API。下面的修改完成了这项工作

SLRequest *postRequest = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodPOST URL:[NSURL URLWithString:@"https://api.twitter.com/1.1/statuses/update_with_media.json"] parameters:nil];

在我发布这篇文章时,不推荐使用\u媒体更新\u。虽然它现在可以工作,但将来可能会突然停止-这可能会使你的应用程序在将来无法工作

在阅读了很多Twitter的API文档之后,我成功地使它工作了,而没有使用“用媒体更新”

上载图像(或视频)所涉及的过程是:

  • 使用/media/upload.json SLRequest首先上载媒体(图像或视频)。使用nil参数并使用 SLRequest的“addMultipartData”方法

  • 对该请求调用performRequestWithHandler

  • 等待twitter的响应,从响应数据中获取“媒体ID”(将数据转换为JSON格式)并检索 将“媒体id字符串”转换为NSString

  • 使用/statuses/update.json启动另一个SLRequest,并将媒体ID(key:Media_ID)一起附加到参数字典中 带有状态文本(键:status)

  • 在第二个SLRequest上调用performRequestWithHandler以提交推文

  • 有关详细代码,请参见我的教程博客:

    但不推荐使用\u媒体更新\u。我想它现在可以工作了,但将来会停止。仅供参考,我也面临着与您相同的问题-使用/statuses/update.json只发布文本,而不是多部分图像。请注意,媒体上载路径为:
    https://upload.twitter.com/1.1/media/upload.json
    它的子域与状态路径不同
    NSDictionary *parameters = @{@"status": @"See my image:",
                                                        @"media_ids": mediaID };