当应用程序处于非活动状态时，iOS处理动态链接

我的申请者：

let customURLScheme = "dlscheme"

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {

FIROptions.default().deepLinkURLScheme = self.customURLScheme
FIRApp.configure()

return true
}

func application(_ app: UIApplication, open url: URL, options: [UIApplicationOpenURLOptionsKey : Any]) -> Bool {
    return application(app, open: url, sourceApplication: nil, annotation: [:])
}

func application(_ application: UIApplication, open url: URL, sourceApplication: String?, annotation: Any) -> Bool {
    let dynamicLink = FIRDynamicLinks.dynamicLinks()?.dynamicLink(fromCustomSchemeURL: url)
    if let dynamicLink = dynamicLink {
        let message = generateDynamicLinkMessage(dynamicLink)
        if #available(iOS 8.0, *) {
            showDeepLinkAlertView(withMessage: message)
        }
        return true
    }
    if #available(iOS 8.0, *) {
        showDeepLinkAlertView(withMessage: "openURL:\n\(url)")
    } else {
    }
    return false
}
@available(iOS 8.0, *)
func application(_ application: UIApplication, continue userActivity: NSUserActivity, restorationHandler: @escaping ([Any]?) -> Void) -> Bool {
    guard let dynamicLinks = FIRDynamicLinks.dynamicLinks() else {
        return false
    }
    let handled = dynamicLinks.handleUniversalLink(userActivity.webpageURL!) { (dynamiclink, error) in
        let message = self.generateDynamicLinkMessage(dynamiclink!)
        self.showDeepLinkAlertView(withMessage: message)
    }
    return handled
}

func generateDynamicLinkMessage(_ dynamicLink: FIRDynamicLink) -> String {
    let matchConfidence: String
    if dynamicLink.matchConfidence == .weak {
        matchConfidence = "Weak"
    } else {
        matchConfidence = "Strong"
    }
    let message = "App URL: \(dynamicLink.url)\nMatch Confidence: \(matchConfidence)\n"
    return message
}

@available(iOS 8.0, *)
func showDeepLinkAlertView(withMessage message: String) {
    let okAction = UIAlertAction.init(title: "OK", style: .default) { (action) -> Void in
        print("OK")
    }

    let alertController = UIAlertController.init(title: "Deep-link Data", message: message, preferredStyle: .alert)
    alertController.addAction(okAction)
    self.window?.rootViewController?.present(alertController, animated: true, completion: nil)
}

这是我的密码。我正在使用firebase dynamic link，并像本教程一样实现它：

这个样本：

当我的应用程序在后台时，它工作得很好。打开应用程序并在我点击动态链接时显示带有url的警报

但如果我的应用程序处于非活动状态（未运行），它将无法工作。只需打开应用程序，什么也不做

我的问题是：当应用程序处于非活动状态时，如何处理动态链接？
对不起，我的英语不好，我不得不这样做

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool
{

 if let option = launchOptions
    {
        if option.keys.contains(UIApplicationLaunchOptionsKey.userActivityDictionary)
        {
            if let userActivityDict = option[UIApplicationLaunchOptionsKey.userActivityDictionary] as? [AnyHashable:Any]
            {
                if userActivityDict.keys.contains(UIApplicationLaunchOptionsKey.userActivityType)
                {
                    if let userActivity = userActivityDict["UIApplicationLaunchOptionsUserActivityKey"] as? NSUserActivity {

                        if let webpageURL = userActivity.webpageURL
                        {
                            // Write your code here.
                        }
                    }
                }
            }
        }
    }
}

---

当应用程序在后台时，没有调用

应用程序（\uu:open:options:）

时，我遇到了一个问题。Firebase SDK使用swizzle方法，这就是原因

我通过在

Info.plist

---

有关其工作原理及其影响的更多详细信息，请阅读此处

Swift 5

您可以通过以下方式进行处理：

AppDelegate.swift

import Firebase
import FirebaseDynamicLinks

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplication.LaunchOptionsKey: Any]?) -> Bool {

    // ... your other code here

    FirebaseApp.configure()

    let activityKey = NSString(string: "UIApplicationLaunchOptionsUserActivityKey")
    if let userActivityDict = launchOptions?[.userActivityDictionary] as? [NSObject : AnyObject], let userActivity = userActivityDict[activityKey] as? NSUserActivity, let webPageUrl = userActivity.webpageURL {
        
        DynamicLinks.dynamicLinks().handleUniversalLink(webPageUrl) { (dynamiclink, error) in
            
            // do some stuff with dynamiclink
            
        }
        
    }
    
    return true
}

---

您成功地使它工作了吗？您的6级（！！）条件检查可以用单个级别

if

或

guard

表示。17行变成5行。

//用dynamiclink做些什么？@TomSawyer取决于你的需要。以我的方式：
如果让url=dynamiclink？.url，让contenttype=url[“contenttype”]，让contentid=url[“contentid”]{…}
我不使用Firebase，但从
调用openURL无法使用选项