Ios 如何使用NSURL将用户电子邮件密码发布到json我有这些信息，就像我有authenticationtoken一样

如何以JSON格式发布用户电子邮件id和密码我已经给出了这些信息，但我得到了错误

如果电子邮件和密码正确，用户必须进入下一个屏幕：

- (IBAction)enterButtonAction:(id)sender {
        NSString *post =[NSString stringWithFormat:@"user[email]=%@&user[password]=%@",[userNameTF text],[passWordTF text],nil];

        NSLog(@"PostData: %@",post);

        NSURL *url=[NSURL URLWithString:@"http:secure.sample.in/login"];
        NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
        NSString *postLength = [NSString stringWithFormat:@"%lu", (unsigned long)[postData length]];
        NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init] ;
        [request setURL:url];
        [request setHTTPMethod:@"POST"];
        [request setValue:postLength forHTTPHeaderField:@"Content-Length"];
        [request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
        [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
        [request setValue:@"vz_Bim-_QYyzgJBmv68R" forHTTPHeaderField:@"authentication_token"];

        [request setHTTPBody:postData];

        NSURLResponse *requestResponse;
        NSData *requestHandler = [NSURLConnection sendSynchronousRequest:request returningResponse:&requestResponse error:nil];

        id dict = [NSJSONSerialization JSONObjectWithData:requestHandler options:0 error:nil];

        NSString *id1 = [dict valueForKey:@"id"];
        NSLog(@"id: %@", id1);

        NSString *email = [dict valueForKey:@"email"];
        NSLog(@"email: %@", email);

        NSString *role = [dict valueForKey:@"role"];
        NSLog(@"role: %@", role);

        NSString *phone= [dict valueForKey:@"phone"];
        NSLog(@"phone: %@", phone);

        NSString *full_name = [dict valueForKey:@"full_name"];
        NSLog(@"full_name: %@", full_name);

        NSString *gender = [dict valueForKey:@"gender"];
        NSLog(@"gender: %@", gender);

        if (!requestResponse) {
            NSLog(@"No Request");
        } else {
            NSLog(@"Success");
        }
    }

---

您只需检查响应结果

-(void) connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response
{   
    if ([response isKindOfClass:[NSHTTPURLResponse class]])
    {
        NSHTTPURLResponse *httpResponse = (NSHTTPURLResponse*) response; 
        //If you need the response, you can use it here
    }
}

---

欲了解更多信息，看到这一点。

我正在等待帮助。您收到了什么错误消息？这不像是错误，我有一个身份验证令牌，通过使用身份验证令牌，我必须验证用户，并允许他下一次屏幕检查requestResponse，如果HTTP状态码为200，这意味着身份验证成功，否则身份验证失败。因此，我必须使用http类