Warning: file_get_contents(/data/phpspider/zhask/data//catemap/9/ios/113.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
iOS应用内购买订阅从SKProduct获得免费试用期长度_Ios_In App Purchase_Storekit_In App Subscription_Skproduct - Fatal编程技术网

iOS应用内购买订阅从SKProduct获得免费试用期长度

iOS应用内购买订阅从SKProduct获得免费试用期长度,ios,in-app-purchase,storekit,in-app-subscription,skproduct,Ios,In App Purchase,Storekit,In App Subscription,Skproduct,我正在使用订阅进行应用内购买。 在swift中,您可以从SKProduct获取价格和价格区域设置,如下所示: weeklyProduct.price.doubleValue weeklyProduct.priceLocale.currencySymbol 其中weeklyProduct是SKProduct 有可能获得免费试用期吗?例如,我为该产品指定了两周的免费试用期。我可以从SKProduct获得此信息吗?试用期不包含在SKProduct信息中,必须硬编码到应用程序中或存储在您的服务器上

我正在使用订阅进行应用内购买。 在swift中,您可以从SKProduct获取价格和价格区域设置,如下所示:

weeklyProduct.price.doubleValue  
weeklyProduct.priceLocale.currencySymbol
其中weeklyProduct是SKProduct


有可能获得免费试用期吗?例如,我为该产品指定了两周的免费试用期。我可以从SKProduct获得此信息吗?

试用期不包含在SKProduct信息中,必须硬编码到应用程序中或存储在您的服务器上。获取此类信息的唯一可用选项(当前)是从收据本身。

从iOS 11.2开始,您可以使用
SKProduct
的属性获取有关试验的信息


它包含类的实例,描述了包括免费试用在内的所有折扣期。

您可以获得它,但如上所述,它只能从iOS 11.2开始工作,对于其他版本,您必须通过API从服务器获得它

下面是我使用的示例代码:

if #available(iOS 11.2, *) {
  if let period = prod.introductoryPrice?.subscriptionPeriod {
     print("Start your \(period.numberOfUnits) \(unitName(unitRawValue: period.unit.rawValue)) free trial")
  }
} else {
  // Fallback on earlier versions
  // Get it from your server via API
}

func unitName(unitRawValue:UInt) -> String {
    switch unitRawValue {
    case 0: return "days"
    case 1: return "weeks"
    case 2: return "months"
    case 3: return "years"
    default: return ""
    }
}
作为灵感,我创建了SKProduct.PeriodUnit的扩展

extension SKProduct.PeriodUnit {
    func description(capitalizeFirstLetter: Bool = false, numberOfUnits: Int? = nil) -> String {
        let period:String = {
            switch self {
            case .day: return "day"
            case .week: return "week"
            case .month: return "month"
            case .year: return "year"
            }
        }()

        var numUnits = ""
        var plural = ""
        if let numberOfUnits = numberOfUnits {
            numUnits = "\(numberOfUnits) " // Add space for formatting
            plural = numberOfUnits > 1 ? "s" : ""
        }
        return "\(numUnits)\(capitalizeFirstLetter ? period.capitalized : period)\(plural)"
    }
}
使用:

if #available(iOS 11.2, *),
    let period = prod?.introductoryPrice?.subscriptionPeriod
{
    let desc = period.unit.description(capitalizeFirstLetter: true, numberOfUnits: period.numberOfUnits)
} else {
    // Fallback
}
let price = product.priceString()
print(price)

这将创建一个格式良好的字符串(例如1天、1周、2个月、2年)

Nice one@scott Wood。我会把它变成
SKProduct.PeriodUnit
的一个属性,而不是一个函数。这将使行为与枚举更加一致:

@available(iOS 11.2, *)
extension SKProduct.PeriodUnit {

    var description: String {
        switch self {
        case .day: return "day"
        case .week: return "week"
        case .month: return "month"
        case .year: return "year"
        // support for future values
        default:
            return "N/A"
        }
    }

    func pluralisedDescription(length: Int) -> String {
        let lengthAndDescription = length.description + " " + self.description
        let plural = length > 1 ?  lengthAndDescription + "s" : lengthAndDescription
        return plural
    }
}
然后是一个函数,根据
description
属性返回复数形式


是的,正如其他人所指出的,如果你的应用程序有其他语言版本,你应该本地化复数。

我已经用DateComponents Formatter解决了这个问题,这为你节省了大量的时间,可以用不同的语言本地化和处理复数等等。 这看起来像是很多代码,但我希望它能在将来节省我的时间

import Foundation

class PeriodFormatter {
    static var componentFormatter: DateComponentsFormatter {
        let formatter = DateComponentsFormatter()
        formatter.maximumUnitCount = 1
        formatter.unitsStyle = .full
        formatter.zeroFormattingBehavior = .dropAll
        return formatter
    }

    static func format(unit: NSCalendar.Unit, numberOfUnits: Int) -> String? {
        var dateComponents = DateComponents()
        dateComponents.calendar = Calendar.current
        componentFormatter.allowedUnits = [unit]
        switch unit {
        case .day:
            dateComponents.setValue(numberOfUnits, for: .day)
        case .weekOfMonth:
            dateComponents.setValue(numberOfUnits, for: .weekOfMonth)
        case .month:
            dateComponents.setValue(numberOfUnits, for: .month)
        case .year:
            dateComponents.setValue(numberOfUnits, for: .year)
        default:
            return nil
        }

        return componentFormatter.string(from: dateComponents)
    }
}
它需要将SKProduct period单位转换为NSCalendarUnit

import StoreKit

@available(iOS 11.2, *)
extension SKProduct.PeriodUnit {
    func toCalendarUnit() -> NSCalendar.Unit {
        switch self {
        case .day:
            return .day
        case .month:
            return .month
        case .week:
            return .weekOfMonth
        case .year:
            return .year
        @unknown default:
            debugPrint("Unknown period unit")
        }
        return .day
    }
}
您可以从订阅期调用它,如下所示:

import StoreKit

@available(iOS 11.2, *)
extension SKProductSubscriptionPeriod {
    func localizedPeriod() -> String? {
        return PeriodFormatter.format(unit: unit.toCalendarUnit(), numberOfUnits: numberOfUnits)
    }
}
你也可以这样打电话给SKProduct折扣。请注意,我目前没有实施其他付款模式

import StoreKit

@available(iOS 11.2, *)
extension SKProductDiscount {
    func localizedDiscount() -> String? {
        switch paymentMode {
        case PaymentMode.freeTrial:
            return "Free trial for \(subscriptionPeriod.localizedPeriod() ?? "a period")"
        default:
            return nil
        }
    }
}

Swift 5

使用和回答作为灵感:

import StoreKit

extension SKProduct {
    func priceString() -> String {
        let period:String = {
            switch self.subscriptionPeriod?.unit {
            case .day: return "day"
            case .week: return "week"
            case .month: return "month"
            case .year: return "year"
            case .none: return ""
            case .some(_): return ""
            }
        }()

        let price = self.localizedPrice!
        let numUnits = self.subscriptionPeriod?.numberOfUnits ?? 0
        let plural = numUnits > 1 ? "s" : ""
        return String(format: "%@ for %d %@%@", arguments: [price, numUnits, period, plural])
    }
}
使用:

if #available(iOS 11.2, *),
    let period = prod?.introductoryPrice?.subscriptionPeriod
{
    let desc = period.unit.description(capitalizeFirstLetter: true, numberOfUnits: period.numberOfUnits)
} else {
    // Fallback
}
let price = product.priceString()
print(price)
结果:

THB 89.00 for 7 days
THB 149.00 for 1 month

下面是swift 5的更紧凑、使用时间更短的版本,扩展了SKProductSubscriptionPeriod

用法:

print("\(period.localizedDescription) free trial")

//Printed example "1 week free trial"
实施:

extension SKProductSubscriptionPeriod {
    public var localizedDescription: String {
        let period:String = {
            switch self.unit {
            case .day: return "day"
            case .week: return "week"
            case .month: return "month"
            case .year: return "year"
            @unknown default:
                return "unknown period"
            }
        }()
    
        let plural = numberOfUnits > 1 ? "s" : ""
        return "\(numberOfUnits) \(period)\(plural)"
    }
}
目标C

#import "SKProduct+SKProduct.h"

-(NSString*_Nullable)localizedTrialDuraion{

if (@available(iOS 11.2, *)) {
    
    NSDateComponentsFormatter *formatter = [[NSDateComponentsFormatter alloc] init];
    [formatter setUnitsStyle:NSDateComponentsFormatterUnitsStyleFull]; //e.g 1 month
    formatter.zeroFormattingBehavior = NSDateComponentsFormatterZeroFormattingBehaviorDropAll;
    NSDateComponents * dateComponents = [[NSDateComponents alloc]init];
    [dateComponents setCalendar:[NSCalendar currentCalendar]];
    
    switch (self.introductoryPrice.subscriptionPeriod.unit) {
        case SKProductPeriodUnitDay:{
            formatter.allowedUnits = NSCalendarUnitDay;
            [dateComponents setDay:self.introductoryPrice.subscriptionPeriod.numberOfUnits];
            break;
        }
        case SKProductPeriodUnitWeek:{
            formatter.allowedUnits = NSCalendarUnitWeekOfMonth;
            [dateComponents setWeekOfMonth:self.introductoryPrice.subscriptionPeriod.numberOfUnits];
            break;
        }
        case SKProductPeriodUnitMonth:{
            formatter.allowedUnits = NSCalendarUnitMonth;
            [dateComponents setMonth:self.introductoryPrice.subscriptionPeriod.numberOfUnits];
            break;
        }
        case SKProductPeriodUnitYear:{
            formatter.allowedUnits = NSCalendarUnitYear;
            [dateComponents setYear:self.introductoryPrice.subscriptionPeriod.numberOfUnits];
            break;
        }
        default:{
            return nil;
            break;
        }
            break;
    }
    [dateComponents setValue:self.introductoryPrice.subscriptionPeriod.numberOfUnits forComponent:formatter.allowedUnits];
    return [formatter stringFromDateComponents:dateComponents];
} else {
    // Fallback on earlier versions
}

return nil;

}

否。您可以从获取信息,说明订阅当前是否处于免费试用期,但不包括免费试用期。好的,谢谢。明白了,回答得很好。如果您想本地化,请使用stringdicts而不是
复数
变量:这是最优雅的解决方案,因为它正确地考虑了本地化。同意,非常好地完成了Roel。