Ios 精灵套件精灵在我的if语句中未向右移动

在xcode中玩的时候，我的游戏底部有一些看起来像小方块的瓷砖。在游戏项目文件附带的更新功能中，我使所有块向左移动。但一旦其中一块瓷砖离开屏幕，我会将其重新定位到另一侧，以使其继续运行，但它会变得静止，不会移动。这是我的代码

override func update(currentTime: CFTimeInterval) {


    tileStone1.position = CGPoint(x: tileStone1.position.x - 4, y: tileStone1.position.y)
    tileStone2.position = CGPoint(x: tileStone2.position.x - 4, y: tileStone2.position.y)
    tileStone3.position = CGPoint(x: tileStone3.position.x - 4, y: tileStone3.position.y)
    tileStone4.position = CGPoint(x: tileStone4.position.x - 4, y: tileStone4.position.y)
    tileStone5.position = CGPoint(x: tileStone5.position.x - 4, y: tileStone5.position.y)
    tileStone6.position = CGPoint(x: tileStone6.position.x - 4, y: tileStone6.position.y)
    tileStone7.position = CGPoint(x: tileStone7.position.x - 4, y: tileStone7.position.y)
    tileStone8.position = CGPoint(x: tileStone8.position.x - 4, y: tileStone8.position.y)
    tileStone9.position = CGPoint(x: tileStone9.position.x - 4, y: tileStone9.position.y)
    tileStone10.position = CGPoint(x: tileStone10.position.x - 4, y: tileStone10.position.y)
    tileStone11.position = CGPoint(x: tileStone11.position.x - 4, y: tileStone11.position.y)
    tileStone12.position = CGPoint(x: tileStone12.position.x - 4, y: tileStone12.position.y)



    if (tileStone1.position.x < self.frame.size.width){

        tileStone1.anchorPoint = CGPointZero

        tileStone1.position = CGPoint(x: 930 - 4, y: tileStone1.position.y)




    }

覆盖函数更新（currentTime:CFTimeInterval）{
tileStone1.position=CGPoint（x:tileStone1.position.x-4，y:tileStone1.position.y）
tileStone2.position=CGPoint（x:tileStone2.position.x-4，y:tileStone2.position.y）
tileStone3.position=CGPoint（x:tileStone3.position.x-4，y:tileStone3.position.y）
tileStone4.position=CGPoint（x:tileStone4.position.x-4，y:tileStone4.position.y）
tileStone5.position=CGPoint（x:tileStone5.position.x-4，y:tileStone5.position.y）
tileStone6.position=CGPoint（x:tileStone6.position.x-4，y:tileStone6.position.y）
tileStone7.position=CGPoint（x:tileStone7.position.x-4，y:tileStone7.position.y）
tileStone8.position=CGPoint（x:tileStone8.position.x-4，y:tileStone8.position.y）
tileStone9.position=CGPoint（x:tileStone9.position.x-4，y:tileStone9.position.y）
tileStone10.position=CGPoint（x:tileStone10.position.x-4，y:tileStone10.position.y）
tileStone11.position=CGPoint（x:tileStone11.position.x-4，y:tileStone11.position.y）
tileStone12.position=CGPoint（x:tileStone12.position.x-4，y:tileStone12.position.y）
if（瓷砖1.position.x

正如Putz1103所建议的，您确实应该使用数组来代替。然后，正如我在评论中所质疑的，也许您希望使用

self.frame.minX

而不是

self.frame.size.width

？（另外，在将来，您可以使用

self.frame.width

代替

self.frame.size.width

）

它不移动的原因当然是因为位置总是小于宽度，这意味着每一帧都会重置位置

非常清楚：

.width

获取屏幕的宽度，比如1024，而

.minX

获取屏幕最左侧的位置，通常为0

override func update(currentTime: CFTimeInterval) {

    tileStone1.position = CGPoint(x: tileStone1.position.x - 4, y: tileStone1.position.y)
    tileStone2.position = CGPoint(x: tileStone2.position.x - 4, y: tileStone2.position.y)
    tileStone3.position = CGPoint(x: tileStone3.position.x - 4, y: tileStone3.position.y)
    tileStone4.position = CGPoint(x: tileStone4.position.x - 4, y: tileStone4.position.y)
    tileStone5.position = CGPoint(x: tileStone5.position.x - 4, y: tileStone5.position.y)
    tileStone6.position = CGPoint(x: tileStone6.position.x - 4, y: tileStone6.position.y)
    tileStone7.position = CGPoint(x: tileStone7.position.x - 4, y: tileStone7.position.y)
    tileStone8.position = CGPoint(x: tileStone8.position.x - 4, y: tileStone8.position.y)
    tileStone9.position = CGPoint(x: tileStone9.position.x - 4, y: tileStone9.position.y)
    tileStone10.position = CGPoint(x: tileStone10.position.x - 4, y: tileStone10.position.y)
    tileStone11.position = CGPoint(x: tileStone11.position.x - 4, y: tileStone11.position.y)
    tileStone12.position = CGPoint(x: tileStone12.position.x - 4, y: tileStone12.position.y)



    if (tileStone1.position.x < self.frame.minX){

        tileStone1.anchorPoint = CGPointZero

        tileStone1.position = CGPoint(x: 930 - 4, y: tileStone1.position.y)
    }
}

它比以下内容短得多，也简单得多：

tileStone.position = CGPoint(x: tileStone.position.x - 4, y: tileStone.position.y)

//or later

tileStone.position = CGPoint(x: 930 - 4, y: tileStone1.position.y)

---

正如Putz1103所建议的，您确实应该使用数组来代替。然后，正如我在评论中所质疑的，也许您希望使用

self.frame.minX

而不是

self.frame.size.width

？（另外，在将来，您可以使用

self.frame.width

而不是

self.frame.size.width

）

它不移动的原因当然是因为位置总是小于宽度，这意味着每一帧都会重置位置

非常清楚：

.width

获取屏幕的宽度，比如1024，而

.minX

获取屏幕最左侧的位置，通常为0

override func update(currentTime: CFTimeInterval) {

    tileStone1.position = CGPoint(x: tileStone1.position.x - 4, y: tileStone1.position.y)
    tileStone2.position = CGPoint(x: tileStone2.position.x - 4, y: tileStone2.position.y)
    tileStone3.position = CGPoint(x: tileStone3.position.x - 4, y: tileStone3.position.y)
    tileStone4.position = CGPoint(x: tileStone4.position.x - 4, y: tileStone4.position.y)
    tileStone5.position = CGPoint(x: tileStone5.position.x - 4, y: tileStone5.position.y)
    tileStone6.position = CGPoint(x: tileStone6.position.x - 4, y: tileStone6.position.y)
    tileStone7.position = CGPoint(x: tileStone7.position.x - 4, y: tileStone7.position.y)
    tileStone8.position = CGPoint(x: tileStone8.position.x - 4, y: tileStone8.position.y)
    tileStone9.position = CGPoint(x: tileStone9.position.x - 4, y: tileStone9.position.y)
    tileStone10.position = CGPoint(x: tileStone10.position.x - 4, y: tileStone10.position.y)
    tileStone11.position = CGPoint(x: tileStone11.position.x - 4, y: tileStone11.position.y)
    tileStone12.position = CGPoint(x: tileStone12.position.x - 4, y: tileStone12.position.y)



    if (tileStone1.position.x < self.frame.minX){

        tileStone1.anchorPoint = CGPointZero

        tileStone1.position = CGPoint(x: 930 - 4, y: tileStone1.position.y)
    }
}

它比以下内容短得多，也简单得多：

tileStone.position = CGPoint(x: tileStone.position.x - 4, y: tileStone.position.y)

//or later

tileStone.position = CGPoint(x: 930 - 4, y: tileStone1.position.y)

---

这段代码告诉我，一旦tile1出现在屏幕上，将其移动到

930-4

。假设它出现在屏幕上，那么下一帧它将移动到

930-4

…你真的应该把所有这些块放在一个数组中，并在它们上面循环，而不是有12个类变量…（tileStone1.position.xtileStone1.anchorPoint=CGPointZero？该代码告诉我，一旦tile1出现在屏幕上，就将其移动到

930-4

。假设它出现在屏幕上，那么下一帧它将移动到

930-4

。你应该这样做真正地把所有这些块放在一个数组中，并在它们上面循环，而不是有12个类变量…（tileStone1.position.xtileStone1.anchorPoint=CGPointZero？我同意你的答案。而且主播点没有意义，所以，对我来说，它可以删除。我同意你的答案。而主播点没有意义，所以，对我来说，它可以删除删除。