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Ios 无法转换类型为';UILabel';到预期的参数类型';字符串';迅速地_Ios_Swift - Fatal编程技术网

Ios 无法转换类型为';UILabel';到预期的参数类型';字符串';迅速地

Ios 无法转换类型为';UILabel';到预期的参数类型';字符串';迅速地,ios,swift,Ios,Swift,我需要关于这个错误的帮助。我无法转换UILabel类型的值到swift中的预期参数类型字符串 import AVFoundation import UIKit class HeroViewController: UIViewController { @IBOutlet weak var nameLbl: UILabel! @IBOutlet weak var heroImgVw: UIImageView! @IBOutlet weak var quirkLbl: UI

我需要关于这个错误的帮助。我无法转换
UILabel类型的值到swift中的预期参数类型
字符串

import AVFoundation
import UIKit

class HeroViewController: UIViewController {

    @IBOutlet weak var nameLbl: UILabel!
    @IBOutlet weak var heroImgVw: UIImageView!
    @IBOutlet weak var quirkLbl: UILabel!
    @IBOutlet weak var characterBtn: UIButton!

    let heroes = Heroes()

    override func viewDidLoad() {
        super.viewDidLoad()

        generateRandomCharacter()
    }


    @IBAction func characterBtnDidTouch(_ sender: Any) {

        generateRandomCharacter()
        let synthesizer = AVSpeechSynthesizer()
        let utterance = AVSpeechUtterance(string: nameLbl)
        utterance.rate = 0.4
        utterance.voice = AVSpeechSynthesisVoice(language: "en-US")
    }

因为,您需要的是标签的文本,而不是标签本身

将let outrance=avspeechoutrance(string:nameLbl)更改为let outrance=avspeechoutrance(string:nameLbl.text)
let utterance = AVSpeechUtterance(string: nameLbl.text)