Ios InstagramKit从URL接收到的验证访问令牌不';行不通
我试图使用Shyambhat的InstagramKit(来自开发分支),但我无法让Ios InstagramKit从URL接收到的验证访问令牌不';行不通,ios,swift,instagram,instagram-api,Ios,Swift,Instagram,Instagram Api,我试图使用Shyambhat的InstagramKit(来自开发分支),但我无法让receivedValidAccessTokenFromURL方法工作 目前我正在使用swift 3.0,代码如下所示(用于测试目的) 我在info.plist中设置了以下内容 InstagramAppClientId:“myid” InstagramAppRedirectURL:' 出于某些原因,instagram不再允许重定向url为app://了。 当我对request.url进行调试时。这向我展示了以下几点
receivedValidAccessTokenFromURL
方法工作
目前我正在使用swift 3.0,代码如下所示(用于测试目的)
我在info.plist中设置了以下内容
InstagramAppClientId:“myid”
InstagramAppRedirectURL:'
出于某些原因,instagram不再允许重定向url为app://了。
当我对request.url进行调试时。这向我展示了以下几点
https://api.instagram.com/oauth/authorize/?client_id=myid&redirect_uri=http%3A//example.com&response_type=token&scope=comments%20relationships%20likes%20follower_list
我希望这里有人有使用此库的经验,可以帮助我。InstagramKit Swift 3.0获取访问令牌: Info.plist(已添加)
控制台结果我已经弄明白了。我所做的如下
func webView(_ webView: UIWebView, shouldStartLoadWith request: URLRequest, navigationType: UIWebViewNavigationType) -> Bool {
do {
if let url = request.url {
if (String(describing: url).range(of: "access") != nil){
try engine.receivedValidAccessToken(from: url)
if let accessToken = engine.accessToken {
NSLog("accessToken: \(accessToken)")
}
}
}
} catch let err as NSError {
print(err.debugDescription)
}
return true
}
我检查url是否包含访问令牌如果包含,那么我将让引擎实际获取访问令牌。出现错误的原因是,当您第一次打开应用程序时,它试图获取访问令牌,但该令牌不可用。是否需要重定向到另一个应用程序?在尝试调用
receivedValidAccessToken
命令error Domain=Foundation.\u genericObjectError code=0”(null)时,它会出现以下错误
相同。有什么想法吗?对不起,我不明白你的问题。此代码不起作用?我得到错误域=Foundation.\u GenericObjCError code=0“(null)”我检查了URL,访问令牌在那里。。。但是receivedValidAccessToken函数失败。
<key>InstagramAppClientId</key>
<string>3ewqrewr23453243244qwrqwefwefgw42</string>
<key>InstagramAppRedirectURL</key>
<string>https://www.instagram.com/</string>
import UIKit
import InstagramKit
class ViewController: UIViewController {
var webView: UIWebView!
override func viewDidLoad() {
super.viewDidLoad()
// deleteChache()
initWebView()
}
func deleteChache() {
URLCache.shared.removeAllCachedResponses()
if let cookies = HTTPCookieStorage.shared.cookies {
for cookie in cookies {
HTTPCookieStorage.shared.deleteCookie(cookie)
}
}
}
}
// MARK: UIWebView
extension ViewController: UIWebViewDelegate {
func initWebView() {
webView = UIWebView(frame: CGRect(x: 0, y: 0, width: UIScreen.main.bounds.width, height: UIScreen.main.bounds.height))
webView.delegate = self
view.addSubview(webView)
authorizationRequestInWebView()
}
func authorizationRequestInWebView() {
let url = InstagramEngine.shared().authorizationURL()
let request = URLRequest(url: url, cachePolicy: .reloadIgnoringLocalAndRemoteCacheData, timeoutInterval: 10.0)
webView.loadRequest(request)
}
func webView(_ webView: UIWebView, shouldStartLoadWith request: URLRequest, navigationType: UIWebViewNavigationType) -> Bool {
do {
if let url = request.url {
try InstagramEngine.shared().receivedValidAccessToken(from: url)
if let accessToken = InstagramEngine.shared().accessToken {
NSLog("accessToken: \(accessToken)")
}
}
} catch let err as NSError {
print(err.debugDescription)
}
return true
}
}
func webView(_ webView: UIWebView, shouldStartLoadWith request: URLRequest, navigationType: UIWebViewNavigationType) -> Bool {
do {
if let url = request.url {
if (String(describing: url).range(of: "access") != nil){
try engine.receivedValidAccessToken(from: url)
if let accessToken = engine.accessToken {
NSLog("accessToken: \(accessToken)")
}
}
}
} catch let err as NSError {
print(err.debugDescription)
}
return true
}