Ios 如何从到UIKit中的SwiftUI视图返回？

我在HostingViewController和UIKit Viewcontroller中有一个SwiftUI。我的目标是通过按下按钮在它们之间切换。问题是我无法实现从HostingViewController内的SwiftUI视图返回UIKit

我可以通过以下segue功能通过我的UIKit ViewController转到HostingViewController：

 @IBSegueAction func swiftUIAction(_ coder: NSCoder) -> UIViewController? {
        return UIHostingController(coder: coder, rootView: WorkoutSelectView())
    }

 func switchBack(){
        guard var rootViewController = (UIApplication.shared.connectedScenes.first?.delegate as? SceneDelegate)?.window?.rootViewController else {
                  return
        }
        let storyboard = UIStoryboard(name: "Main", bundle: nil)
        let controller = storyboard.instantiateViewController(withIdentifier: "Home") as! HomeViewController
        rootViewController.present(controller, animated: true, completion: { () -> Void in
        
        })
    }

我尝试过的

但我不知道如何回去。我使用了一种解决方案，在这里，我从SwiftUI视图的AppDelegate调用函数：

 guard let appDelegate: AppDelegate = UIApplication.shared.delegate as? AppDelegate else { return }
 appDelegate.switchBack()

在Appdelegate中，我有一个函数：

 @IBSegueAction func swiftUIAction(_ coder: NSCoder) -> UIViewController? {
        return UIHostingController(coder: coder, rootView: WorkoutSelectView())
    }

 func switchBack(){
        guard var rootViewController = (UIApplication.shared.connectedScenes.first?.delegate as? SceneDelegate)?.window?.rootViewController else {
                  return
        }
        let storyboard = UIStoryboard(name: "Main", bundle: nil)
        let controller = storyboard.instantiateViewController(withIdentifier: "Home") as! HomeViewController
        rootViewController.present(controller, animated: true, completion: { () -> Void in
        
        })
    }

这很酷，但问题是：

<WorkoutTracker.HomeViewController: 0x148f072a0>) whose view is not in the window hierarchy.

），其视图不在窗口层次结构中。

---

您有什么想法吗？

可能的方法是将完成回调传递到您的SwiftUI视图中，如下面的简化演示所示

struct WorkoutSelectView: View {
    var completion: () -> () = {}

    var body: some View {
        Button("Close", action: completion)
    }
}

并在UIViewController中使用此回调来取消显示的控制器，如

@IBSegueAction func swiftUIAction(_ coder: NSCoder) -> UIViewController? {
   let controller =  UIHostingController(coder: coder, 
        rootView: WorkoutSelectView() { [weak self] in
           self?.dismiss(true)
        })
   return controller
}