如果应用程序在ios中处于活动状态，如何在收到通知时发出声音？

请给我一个解决方案，当应用程序运行时，如果立即收到通知，我如何获得声音？我正在使用x-code 6.3？

您可以手动添加声音文件，并在应用程序处于活动状态时播放

-(void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo
{
     [[NSNotificationCenter defaultCenter] postNotificationName:@"MessageReceived" object:self];

    UIApplicationState state = [application applicationState];
    if (state == UIApplicationStateActive)
    {

//        NSString *cancelTitle = @"Close";
        NSString *showTitle = @"Show";
//        NSString *message = [[userInfo valueForKey:@"aps"] valueForKey:@"alert"];
        UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:@"New Order"
                                                            message:@"You just received new order"
                                                           delegate:self
                                                  cancelButtonTitle:nil
                                                     otherButtonTitles:showTitle, nil];

        UILocalNotification *localNotifcation = [[UILocalNotification alloc] init];
        localNotifcation.userInfo = userInfo;
        localNotifcation.soundName = UILocalNotificationDefaultSoundName;
//        localNotifcation.alertBody = message;
        localNotifcation.fireDate = [NSDate date];
        [[UIApplication sharedApplication] scheduleLocalNotification:localNotifcation];

        [alertView show];

    }
    else {
        //Do stuff that you would do if the application was not active
    }
}

有关更多默认声音，请检查以下答案：

---

希望它有助于添加以下框架

if ([application applicationState] == UIApplicationStateActive) {
        NSLog(@"active");

      NSString *soundPath = [[NSBundle mainBundle] pathForResource:@"alarm2" ofType:@"wav"];
        NSURL *soundURL = [NSURL fileURLWithPath:soundPath];
        AudioServicesCreateSystemSoundID((__bridge CFURLRef)soundURL, &_mySound);
        AudioServicesPlaySystemSound(self.mySound);
    }

或您可以使用系统声音-

- (void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo
{

    UIApplicationState state = [application applicationState];
    if (state == UIApplicationStateActive)
    {

        SystemSoundID soundID;
        CFBundleRef mainBundle = CFBundleGetMainBundle();
        CFURLRef ref = CFBundleCopyResourceURL(mainBundle, (CFStringRef)@"mySoundName.wav", NULL, NULL);
        AudioServicesCreateSystemSoundID(ref, &soundID);
        AudioServicesPlaySystemSound(soundID);
    }
    else {
        // Push Notification received in the background
    }
}

对于振动-

AudioServicesPlaySystemSound(1007);

---

查看所有声音列表

试试这段代码。在

AppDelegate

.m中输入

didReceiveMotonification

的此代码

AudioServicesPlaySystemSound(kSystemSoundID_Vibrate);

---

这段代码非常适合我。

您可以使用带有自定义铃声的音频播放器来播放。我必须将mySoundName.wav文件添加到项目中？是的，否则您可以使用AudioServicesPlaySystemSound（1007）直接播放系统；请参阅我上面的帖子，了解声音代码AudioServicesPlaySystemSound（1007）；有可能更改通知的标题吗？不，我认为不可能，它总是以标题形式显示您的姓名。有可能更改通知的标题吗？不可能。请阅读这些文件。

AudioServicesPlaySystemSound(kSystemSoundID_Vibrate);

SystemSoundID soundID;
    CFBundleRef mainBundle = CFBundleGetMainBundle();
    CFURLRef ref = CFBundleCopyResourceURL(mainBundle, (CFStringRef)@"Voicemail.wav", NULL, NULL);
    AudioServicesCreateSystemSoundID(ref, &soundID);
    AudioServicesPlaySystemSound(soundID);