Ios 如何调整文本大小而不显示。。。在UIPickerView？

我用了3个PickerView，有几个词很大，不适合PickerView，看起来像这样“IamAWordVer…”，我不希望这种情况发生。我希望它调整字体大小或类似的东西来适应PickerView中的所有单词，但我不想影响PickerView的大小或其他picker视图的字体大小，包括发生在这个PickerView中的单词

例如，所有单词都使用默认值，如果不适合，请调整大小以适合所有单词

func pickerView(pickerView: UIPickerView, viewForRow row: Int, forComponent component: Int, reusingView view: UIView?) -> UIView {
    let pickerLabel = UILabel()

    if pickerView == pvOne{
        pickerLabel.adjustsFontSizeToFitWidth = true
        pickerLabel.attributedText = oneText[row] as? NSAttributedString
    }
    else if(pickerView == pvTwo){
        pickerLabel.adjustsFontSizeToFitWidth = true
        pickerLabel.attributedText = twoText[row] as? NSAttributedString
    }
    else if(pickerView == pvThree){
        pickerLabel.adjustsFontSizeToFitWidth = true
        pickerLabel.attributedText = threeText[row] as? NSAttributedString
    }
    return pickerLabel
}

---

它现在显示全部为空

使用

nameOfLabel.adjustsFontSizeToFitWidth=true

。

我这样解决：

func pickerView(pickerView: UIPickerView, viewForRow row: Int, forComponent component: Int, reusingView view: UIView?) -> UIView {
    let pickerLabel = UILabel()


    if pickerView == pvOne{
        pickerLabel.adjustsFontSizeToFitWidth = true
        let titleData = oneText[row]
        let myTitle = NSAttributedString(string: titleData as! String, attributes: [NSFontAttributeName:UIFont(name: "Georgia", size: 20.0)!,NSForegroundColorAttributeName:UIColor.blackColor()])
        pickerLabel.attributedText = myTitle

    }
    else if(pickerView == pvTwo){
        pickerLabel.adjustsFontSizeToFitWidth = true
        let titleData = twoText[row]
        let myTitle = NSAttributedString(string: titleData as! String, attributes: [NSFontAttributeName:UIFont(name: "Georgia", size: 20.0)!,NSForegroundColorAttributeName:UIColor.blackColor()])
        pickerLabel.attributedText = myTitle
    }
    else if(pickerView == pvThree){
        pickerLabel.adjustsFontSizeToFitWidth = true
        let titleData = threeText[row]
        let myTitle = NSAttributedString(string: titleData as! String, attributes: [NSFontAttributeName:UIFont(name: "Georgia", size: 20.0)!,NSForegroundColorAttributeName:UIColor.blackColor()])
        pickerLabel.attributedText = myTitle
    }
    return pickerLabel
}

---

您正在将字符串强制转换为NSAttributedString

尝试：

---

是的，假设他们正在使用

pickerView:viewForRow:forComponent:reusingView:

delegate方法并传递一个标签。我正在这个

func pickerView中尝试这样做（pickerView:UIPickerView，viewForRow:Int，forComponent:Int，reusingView:UIView？）->UIView

但是我不知道我在哪里使用了我试图在里面使用的标签的名称

让pickerLabel=UILabel（）

但是这是一个新的更新你的问题，你的

pickerView:viewForRow:forComponent:reusingView:

方法。更新了，我想这就是你问的。剩下的代码呢？您发布的内容只返回一个空标签。您在发布问题之前是否使用了此方法？您在哪里声明pvOne、PVTOW等

func pickerView(pickerView: UIPickerView, viewForRow row: Int, forComponent component: Int, reusingView view: UIView?) -> UIView {
    let pickerLabel = UILabel()

    if pickerView == pvOne{
        pickerLabel.adjustsFontSizeToFitWidth = true
        pickerLabel.text = oneText[row]
    }
    else if(pickerView == pvTwo){
        pickerLabel.adjustsFontSizeToFitWidth = true
        pickerLabel.text = twoText[row]
    }
    else if(pickerView == pvThree){
        pickerLabel.adjustsFontSizeToFitWidth = true
        pickerLabel.text = threeText[row]
    }
    return pickerLabel
}