Ios 解析好友请求处理

我正在parse中进行查询，以检查好友请求。查询返回对象，我可以记录它们。现在，当我将其转换为PFUSER和

NSLog

时，它会因错误而崩溃：

键“FirstName”没有数据。在获取其值之前，请调用fetchIfNeeded。“

请在此处帮助我

PFQuery * friendQuery = [PFQuery queryWithClassName:@"friendship"];

[friendQuery whereKey:@"toUser" equalTo:[PFUser currentUser]];
[friendQuery whereKey:@"status" equalTo:@"Pending"];
[friendQuery findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) {
    if (error)
    {
        //NSLog error
    }
    else {
        NSLog(@"friendRequestCount = %d", objects.count);

        PFObject *object=[objects objectAtIndex:0];
        NSLog(@"%@", object);

        self.friendRequestArray= objects;
        NSLog(@"%@",object[@"toUser"]);

        PFUser *user1= object[@"toUser"];
        NSString *friendName = [NSString stringWithFormat:@"%@ %@",user1[@"FirstName"], user1[@"LastName"] ];
        NSLog(@"name= %@",friendName);

    }
}];

---

你可以使用1或2，我有评论下面的代码，而不是测试

PFQuery * friendQuery = [PFQuery queryWithClassName:@"friendship"];

[friendQuery whereKey:@"toUser" equalTo:[PFUser currentUser]];
[friendQuery whereKey:@"status" equalTo:@"Pending"];
//1
[friendQuery includeKey:@"toUser"];
[friendQuery findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) {
if (error)
{
    //NSLog error
}
else {
    NSLog(@"friendRequestCount = %d", objects.count);

    PFObject *object=[objects objectAtIndex:0];
    NSLog(@"%@", object);

    self.friendRequestArray= objects;
    NSLog(@"%@",object[@"toUser"]);

    PFUser *user1= object[@"toUser"];

    //2 Change PFUser to PFObject
    PFObject *user1 = object[@"toUser"];
    [user1 fetchIfNeeded];

    NSString *friendName = [NSString stringWithFormat:@"%@ %@",user1[@"FirstName"], user1[@"LastName"] ];
    NSLog(@"name= %@",friendName);

}
}];

---

非常感谢HoanNguyen，这很有效。我用了1.朋友，如果你能帮助我理解，那是什么[friendQuery includeKey:@“toUser”]；做我真的不明白。@AbinGeorge如果不使用它，查询中的友谊对象只有一个toUser存根，带有指向用户对象的指针。如果您使用includeKey，那么完整的用户对象将与友谊对象一起返回谢谢你，帅哥和HoanNguyen，现在我明白了