Ios 带按住和释放操作的UIB按钮

我想创建一个可以按住的UIButton，当按住它时，它会调用一次“按住”操作。 当它被释放时，调用“hold was release”操作

此代码无法正常工作，因为触摸可能会在按钮内部移动，并且事件的触发顺序不正确

[button handleControlEvent:UIControlEventTouchDown withBlock:^{
        [self performMomentaryAction:PXActionTypeTouchDown];
    }];
[button handleControlEvent:UIControlEventTouchUpInside withBlock:^{
        [self performMomentaryAction:PXActionTypeTouchUp];
    }];

句柄控制事件基于UIBUtton+块实现

将触地、触地内、触地外事件添加到ur按钮中

 -(IBAction)theTouchDown:(id)sender
 {

    timer = [NSTimer scheduledTimerWithTimeInterval:0.2
                                             target:self
                                           selector:@selector(performFunctionality)
                                           userInfo:nil
  }
-(IBAction)theTouchUpInside:(id)sender
{
[timer invalidate];
timer = nil;
[self performFunctionality];

 }


 -(IBAction)theTouchUpOutside:(id)sender
 {
[timer invalidate];
timer = nil;
 }

-(void)performFunctionality
 {
 //write your logic
 }

试试这个

  UIButton *aButton = [UIButton buttonWithType:UIButtonTypeRoundedRect];
  aButton.frame = CGRectMake(xValue, yValue, 45, 45);
  [aButton addTarget:self action:@selector(holdDown) forControlEvents:UIControlEventTouchDown];
  [aButton addTarget:self action:@selector(holdRelease) forControlEvents:UIControlEventTouchUpInside];


 - (void)holdDown
  {
     NSLog(@"hold Down");
  }

  - (void)holdRelease
  {
      NSLog(@"hold release");

  }

对于NSPratik的情况：如果用户长按按钮，并且在一段时间后，用户不会松开手指，而是将其手指移出按钮的边界，则可以使用事件

uicontrolEventTouchOutside

。只需再添加一个事件

  UIButton *aButton = [UIButton buttonWithType:UIButtonTypeRoundedRect];
  aButton.frame = CGRectMake(xValue, yValue, 45, 45);
  [aButton addTarget:self action:@selector(holdDown) forControlEvents:UIControlEventTouchDown];
  [aButton addTarget:self action:@selector(holdRelease) forControlEvents:UIControlEventTouchUpInside];
  [aButton addTarget:self action:@selector(holdReleaseOutSide) forControlEvents:UIControlEventTouchUpOutside]; //add this for your case releasing the finger out side of the button's frame

 //add this method along with other methods 
  - (void)holdReleaseOutSide
  {
     NSLog(@"hold release out side");
  }

Swift版本

 var  aButton:UIButton = UIButton.buttonWithType(UIButtonType.Custom) as UIButton
 aButton.frame = CGRectMake(xValue,yValue, 45, 45)
 aButton.setTitle("aButton", forState: UIControlState.Normal)
 aButton.backgroundColor = UIColor.greenColor()
 aButton.addTarget(self, action: Selector("holdRelease:"), forControlEvents: UIControlEvents.TouchUpInside);
 aButton.addTarget(self, action: Selector("HoldDown:"), forControlEvents: UIControlEvents.TouchDown)
 self.addSubview(aButton)

 //target functions   
 func HoldDown(sender:UIButton)
 {
    print("hold down")
 }

 func holdRelease(sender:UIButton)
 {
    print("hold release")
 }

从工具（窗格）中拖动一个按钮并右键单击。将出现一个列表，找到“内部润色”，单击并拖动文本前面的圆点，将其移动到viewcontroller.h并定义名称，然后在viewcontroller.m中执行此操作

nslog（“点击进入”）
重复触碰的所有操作，并从列表中找到合适的事件。您需要连接以下两个事件1.触碰，2.触碰内部的iAction方法。在Interface Builder中会很有趣。但是，您也可以使用addTarget:action:forControlEvents:
以编程方式执行此操作。我自己也遇到过这个问题，我们主要使用这些事件：-

//此事件运行良好，并引发火灾

[aButton addTarget:self action:@selector(holdDown) forControlEvents:UIControlEventTouchDown];

//这根本不着火

[aButton addTarget:self action:@selector(holdRelease) forControlEvents:UIControlEventTouchUpInside];

解决方案：-

 -(IBAction)theTouchDown:(id)sender
 {

    timer = [NSTimer scheduledTimerWithTimeInterval:0.2
                                             target:self
                                           selector:@selector(performFunctionality)
                                           userInfo:nil
  }
-(IBAction)theTouchUpInside:(id)sender
{
[timer invalidate];
timer = nil;
[self performFunctionality];

 }


 -(IBAction)theTouchUpOutside:(id)sender
 {
[timer invalidate];
timer = nil;
 }

-(void)performFunctionality
 {
 //write your logic
 }

使用长按手势识别器：-

 UILongPressGestureRecognizer *btn_LongPress_gesture = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(handleBtnLongPressgesture:)];
[aButton addGestureRecognizer:btn_LongPress_gesture];

手势的实施：

- (void)handleBtnLongPressgesture:(UILongPressGestureRecognizer *)recognizer{


//as you hold the button this would fire

if (recognizer.state == UIGestureRecognizerStateBegan) {

    [self holdDown];
}

//as you release the button this would fire

if (recognizer.state == UIGestureRecognizerStateEnded) {

    [self holdRelease];
}
}

您可以使用计时器和按钮修补来处理此操作


 var timer: Timer?

    @IBAction func dowm(_ sender: UIButton) {
        timer = Timer.scheduledTimer(withTimeInterval: 0.3, repeats: true, block: { (time) in
            print("im hold in ")
        })
    }

    @IBAction func up(_ sender: UIButton) {
        timer!.invalidate()

    }


这两个@iAction用于手柄触碰和触碰按钮
当按下按钮时，定时器启动并打印一些内容，当按下按钮时，定时器失效

从Github访问已完成的项目：

我的最佳解决方案是将以下内容复制到viewDidLoad中：

// This will start your action.
hornTouchUp.addTarget(self, action: #selector(start), for: .touchDown)

// This will end your action.
hornTouchUp.addTarget(self, action: #selector(end), for: .touchUpInside)

并将这些函数放在同一文件中的
viewDidLoad
下：

@objc func start() { print("start() triggered."); }
@objc func end() { print("end() triggered"); }

这种方法是我在stackoverflow（iOS 7.1.，Xcode 5.1.）上找到的所有相同答案中唯一有效的方法。它对我有效。但是，有一种情况下，这是行不通的。如果用户长按按钮，一段时间后，用户不会松开手指，而是将手指移出按钮的边界。在这种情况下，
holdRelease
将不会被调用。。。