Ios UINavigationController返回到多个步骤

是否可以在UINavigationController中弹出多个viewcontroller？假设我想后退两步。

是的，你可以通过做类似的事情来实现

//Your navigation controller
UINavigationController *nav;

//Get the view controller that is 2 step behind
UIViewController *controller = [nav.viewControllers objectAtIndex:nav.viewControllers.count - 2];

//Go to that controller
[nav popToViewController:controller animated:YES];

Swift

在swift中，Omar提出的相同解决方案为：

// Get the previous Controller.
let targetController: UIViewController = navigationController!.viewControllers[navigationController!.viewControllers.count - 2]

// And go to that Controller
navigationController?.popToViewController(targetController, animated: true)

在我的情况下，我需要备份2个控制器，因此，我必须在堆栈中进行第3次备份。我真正的解决办法是：

// obtaining origin controller
let controller: UIViewController = navigationController!.viewControllers[navigationController!.viewControllers.count - 2]

// If was the expected controller (An enroll action)
if controller is CreateChatViewController {

    // I get the previous controller from it, in this case, the 3rd back in stack
    let newControllerTarget = navigationController!.viewControllers[navigationController!.viewControllers.count - 3]

    // And finally sends back to desired controller
    navigationController?.popToViewController(newControllerTarget, animated: true)
}