Ios 如何修复线程1:EXC\u BAD\u访问（代码=1，地址=0x58）xcode

我试图用按钮播放一些声音文件，但按下按钮会在第1行出现以下错误线程：EXC_BAD_ACCESS（code=1，address=0x58）

我已经寻找了可能的解决方案，但我找不到与该错误相关的任何东西，我的代码的功能在打印之前运行良好，这是我的完整代码

import UIKit
import AVFoundation

class ViewController: UIViewController {

    var track: String? = nil
    var audioPlayer = AVAudioPlayer()

    @IBAction func heavyButton(_ sender: Any) {
        track = "H"
        print("heavy machine gun \(track!)")
        reproducirAudio(audio: track!)
        audioPlayer.play()
    }

    func reproducirAudio(audio: String) {
        do {
            print("entro a la funcion de reproducir")
            audioPlayer = try AVAudioPlayer(contentsOf: URL.init(fileURLWithPath: Bundle.main.path(forResource: audio, ofType: "mp3")!))
            audioPlayer.prepareToPlay()
        } catch {
            print(error)
        }
    }
}

---

我找到了一个解决方案，这是针对iOS13的

import UIKit
import AVFoundation

class ViewController: UIViewController {

    var track: String? = nil
    var audioPlayer: AVAudioPlayer?

@IBAction func heavyButton(_ sender: Any) {
    track = "H"
    print("heavy machine gun \(track!)")
    reproducirAudio(audio: track!)
}

func reproducirAudio(audio: String) {
    let path = Bundle.main.path(forResource: "\(audio).mp3", ofType:nil)!
    let url = URL(fileURLWithPath: path)

    do {
       audioPlayer = try AVAudioPlayer(contentsOf: url)
       audioPlayer?.play()
    } catch {
        // couldn't load file :(
      }
}

---

你确定

reproductiraudio

能够构建

AVAudioPlayer

实例吗？你说的是

Bundle.main.path（forResource:audio，of type:“mp3”）。这意味着：“如果你找不到文件，请崩溃我的程序。”这就是你要求的，这就是正在发生的事情。请注意，发生这种情况时，您不会捕获错误；这是一个例外，不是一个错误。两个潜在的错误：如果
URL.init（fileURLWithPath:Bundle.main.path（forResource:audio，of type:“mp3”）
为零，您将崩溃。但iOS 13中还有一个新行为：不做
var audioPlayer=AVAudioPlayer（）
。doc.Cf.等中不再有“无参数的init”。
import UIKit
import AVFoundation

class ViewController: UIViewController {

    var track: String? = nil
    var audioPlayer: AVAudioPlayer?

@IBAction func heavyButton(_ sender: Any) {
    track = "H"
    print("heavy machine gun \(track!)")
    reproducirAudio(audio: track!)
}

func reproducirAudio(audio: String) {
    let path = Bundle.main.path(forResource: "\(audio).mp3", ofType:nil)!
    let url = URL(fileURLWithPath: path)

    do {
       audioPlayer = try AVAudioPlayer(contentsOf: url)
       audioPlayer?.play()
    } catch {
        // couldn't load file :(
      }
}