如何在解析iOS中从同一个键获取数据?

如何在解析iOS中从同一个键获取数据?,ios,parse-platform,Ios,Parse Platform,我是Parse.com的新手,我尝试用相同的键从Parse表中获取数据,但值与 -(void)getdata { NSMutableArray *allObjects = [NSMutableArray array]; NSUInteger limit = 1000; __block NSUInteger skip = 0; PFQuery *query = [PFQuery queryWithClassName:@"MapInfo"]; PFQuery *query = [PFQuery qu

我是Parse.com的新手,我尝试用相同的键从Parse表中获取数据,但值与

-(void)getdata
{
NSMutableArray *allObjects = [NSMutableArray array];
NSUInteger limit = 1000;
__block NSUInteger skip = 0;
PFQuery *query = [PFQuery queryWithClassName:@"MapInfo"];
PFQuery *query = [PFQuery queryWithClassName:@"MapInfo"];
[query whereKey:@"Type" containedIn:@[@"Temopary", @"Business"]];
[query setLimit: limit];
[query setSkip: skip];
[query findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error)      {
    if (!error) {
        [allObjects addObjectsFromArray:objects];
        if (objects.count == limit) {

            skip += limit;
            [query setSkip: skip];
            [query findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) {
                [allObjects addObjectsFromArray:objects];
                self.lqpinname=[allObjects valueForKey:@"GPIN"];
                NSLog(@"Qpin name COunt %@",self.lqpinname);
                self.locationArray=[allObjects valueForKey:@"Location"];
                self.llatitude=[self.locationArray valueForKey:@"lat"];
                self.llongitude=[self.locationArray valueForKey:@"lng"];
                self.laddress=[allObjects valueForKey:@"Address"];
                self.lusernameArray=[allObjects valueForKey:@"AddedBy"];
                hudView.hidden=TRUE;
            }];
        }
    }
    else
    {
        NSLog(@"Error: %@ %@", error, [error userInfo]);
    }
}];
}   
但这里是return
Null
value,我想从表中获取数据,其中column
Type=Business&Temporary
请给我解决方案


谢谢

您应该能够使用
whereKey:containedIn:
来执行此操作

PFQuery *query = [PFQuery queryWithClassName:@"MapInfo"];
[query whereKey:@"Type" containedIn:@[@"Temopary", @"Business"]];

您在“临时”中也有输入错误(除非“临时”是什么)-不确定这是否是故意的。

它不起作用。显示我的更新问题我按照您的说法编写代码,但它不会返回任何值。这里的@“Temopary”和@“Business”不是数组,它只是字符串。您的代码看起来是正确的。请检查您是否参考了正确的表格或拼写错误,或者您是否使用了正确的应用程序密钥等。。。我的意思是,除了代码之外,还要检查所有其他的问题