如何在解析iOS中从同一个键获取数据?
我是Parse.com的新手,我尝试用相同的键从Parse表中获取数据,但值与如何在解析iOS中从同一个键获取数据?,ios,parse-platform,Ios,Parse Platform,我是Parse.com的新手,我尝试用相同的键从Parse表中获取数据,但值与 -(void)getdata { NSMutableArray *allObjects = [NSMutableArray array]; NSUInteger limit = 1000; __block NSUInteger skip = 0; PFQuery *query = [PFQuery queryWithClassName:@"MapInfo"]; PFQuery *query = [PFQuery qu
-(void)getdata
{
NSMutableArray *allObjects = [NSMutableArray array];
NSUInteger limit = 1000;
__block NSUInteger skip = 0;
PFQuery *query = [PFQuery queryWithClassName:@"MapInfo"];
PFQuery *query = [PFQuery queryWithClassName:@"MapInfo"];
[query whereKey:@"Type" containedIn:@[@"Temopary", @"Business"]];
[query setLimit: limit];
[query setSkip: skip];
[query findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) {
if (!error) {
[allObjects addObjectsFromArray:objects];
if (objects.count == limit) {
skip += limit;
[query setSkip: skip];
[query findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) {
[allObjects addObjectsFromArray:objects];
self.lqpinname=[allObjects valueForKey:@"GPIN"];
NSLog(@"Qpin name COunt %@",self.lqpinname);
self.locationArray=[allObjects valueForKey:@"Location"];
self.llatitude=[self.locationArray valueForKey:@"lat"];
self.llongitude=[self.locationArray valueForKey:@"lng"];
self.laddress=[allObjects valueForKey:@"Address"];
self.lusernameArray=[allObjects valueForKey:@"AddedBy"];
hudView.hidden=TRUE;
}];
}
}
else
{
NSLog(@"Error: %@ %@", error, [error userInfo]);
}
}];
}
但这里是returnNull
value,我想从表中获取数据,其中columnType=Business&Temporary
请给我解决方案
谢谢 您应该能够使用
whereKey:containedIn:
来执行此操作
PFQuery *query = [PFQuery queryWithClassName:@"MapInfo"];
[query whereKey:@"Type" containedIn:@[@"Temopary", @"Business"]];
您在“临时”中也有输入错误(除非“临时”是什么)-不确定这是否是故意的。它不起作用。显示我的更新问题我按照您的说法编写代码,但它不会返回任何值。这里的@“Temopary”和@“Business”不是数组,它只是字符串。您的代码看起来是正确的。请检查您是否参考了正确的表格或拼写错误,或者您是否使用了正确的应用程序密钥等。。。我的意思是,除了代码之外,还要检查所有其他的问题