Iphone 从NSArray取同一生日的名字
我有一系列的字典,以生日和名字为键。我想检索具有相同生日的名称的值Iphone 从NSArray取同一生日的名字,iphone,ios,nsstring,nsdate,Iphone,Ios,Nsstring,Nsdate,我有一系列的字典,以生日和名字为键。我想检索具有相同生日的名称的值 for (NSDictionary *contactDict in contactList) { NSString *birthdayStr = [contactDict objectForKey:BIRTHDAY_KEY]; } 我应该怎么做才能得到相同生日的名字数组 这就是你要找的吗 for (NSDictionary *contactDict in contactList) { N
for (NSDictionary *contactDict in contactList) {
NSString *birthdayStr = [contactDict objectForKey:BIRTHDAY_KEY];
}
我应该怎么做才能得到相同生日的名字数组 这就是你要找的吗
for (NSDictionary *contactDict in contactList) {
NSString *birthdayStr = [contactDict objectForKey:BIRTHDAY_KEY];
// indexes of all array objects with same birthday:
NSIndexSet *matching = [contactList indexesOfObjectsPassingTest:^BOOL(NSDictionary *contactDict, NSUInteger idx, BOOL *stop) {
return [[contactDict objectForKey:BIRTHDAY_KEY] isEqualToString:birthdayStr];
}];
NSArray *matchingNames = [[contactList objectsAtIndexes:matching] valueForKey:NAME_KEY];
NSLog(@"%@", matchingNames);
}
或者,如果每个不同的生日只需要一个名称数组:
// Set of all distinct birthdays:
NSSet *allBirthdays = [NSSet setWithArray:[contactList valueForKey:BIRTHDAY_KEY]];
for (NSString *birthdayStr in allBirthdays) {
NSLog(@"birthday: %@", birthdayStr);
NSIndexSet *matching = [contactList indexesOfObjectsPassingTest:^BOOL(NSDictionary *contactDict, NSUInteger idx, BOOL *stop) {
return [[contactDict objectForKey:BIRTHDAY_KEY] isEqualToString:birthdayStr];
}];
NSArray *matchingNames = [[contactList objectsAtIndexes:matching] valueForKey:NAME_KEY];
NSLog(@"names: %@", matchingNames);
}
示例数据的输出:
这就是你要找的吗
for (NSDictionary *contactDict in contactList) {
NSString *birthdayStr = [contactDict objectForKey:BIRTHDAY_KEY];
// indexes of all array objects with same birthday:
NSIndexSet *matching = [contactList indexesOfObjectsPassingTest:^BOOL(NSDictionary *contactDict, NSUInteger idx, BOOL *stop) {
return [[contactDict objectForKey:BIRTHDAY_KEY] isEqualToString:birthdayStr];
}];
NSArray *matchingNames = [[contactList objectsAtIndexes:matching] valueForKey:NAME_KEY];
NSLog(@"%@", matchingNames);
}
或者,如果每个不同的生日只需要一个名称数组:
// Set of all distinct birthdays:
NSSet *allBirthdays = [NSSet setWithArray:[contactList valueForKey:BIRTHDAY_KEY]];
for (NSString *birthdayStr in allBirthdays) {
NSLog(@"birthday: %@", birthdayStr);
NSIndexSet *matching = [contactList indexesOfObjectsPassingTest:^BOOL(NSDictionary *contactDict, NSUInteger idx, BOOL *stop) {
return [[contactDict objectForKey:BIRTHDAY_KEY] isEqualToString:birthdayStr];
}];
NSArray *matchingNames = [[contactList objectsAtIndexes:matching] valueForKey:NAME_KEY];
NSLog(@"names: %@", matchingNames);
}
示例数据的输出:
你说同样的生日是什么意思?比如,当你有一个生日字符串时,得到它对应的所有名字?或者得到一个生日在某处重复的所有名字的列表?假设Dict的值为1/12/13,a;1/12/13,B;2/12/13,C。那么我需要一个数组,用于1/12/13和2/12/13,作为(A,B)和C。你说的相同的生日是什么意思?比如,当你有一个生日字符串时,得到它对应的所有名字?或者得到一个生日在某处重复的所有名字的列表?假设Dict的值为1/12/13,a;1/12/13,B;2/12/13,C。然后我需要一个1/12/13和2/12/13的数组作为(A,B)和C。Thnx martin。这正是我要找的…多谢了Hnx martin。这正是我要找的…多谢了