Iphone 手势识别器和按钮动作

我的视图层次结构如下所示：

UIView (A)
UIView > UIImageView
UIView > UIView (B)
UIView > UIView (B) > Rounded Rect Button
UIView > UIView (B) > UIImageView
UIView > UIView (B) > UILabel

我已将手势识别器连接到UIView（B）。我面临的问题是，对于UIView（B）中的Rounded Rect按钮，我没有得到任何操作。singleTap手势识别器捕获/覆盖按钮的触动内部事件

我怎样才能让它工作？我认为响应者链层次结构将确保按钮触摸事件将被优先考虑，它将被触发！我错过了什么

以下是一些相关代码：

#pragma mark -
#pragma mark View lifecycle (Gesture recognizer setup)

- (void)viewDidLoad {
    [super viewDidLoad];

    // double tap gesture recognizer
    UITapGestureRecognizer *dtapGestureRecognize = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(doubleTapGestureRecognizer:)];
    dtapGestureRecognize.delegate = self;
    dtapGestureRecognize.numberOfTapsRequired = 2;
    [self.viewB addGestureRecognizer:dtapGestureRecognize];

    // single tap gesture recognizer
    UITapGestureRecognizer *tapGestureRecognize = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(singleTapGestureRecognizer:)];
    tapGestureRecognize.delegate = self;
    tapGestureRecognize.numberOfTapsRequired = 1;
    [tapGestureRecognize requireGestureRecognizerToFail:dtapGestureRecognize];
    [self.viewB addGestureRecognizer:tapGestureRecognize];

    // add gesture recodgnizer to the grid view to start the edit mode
    UILongPressGestureRecognizer *pahGestureRecognizer = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(longPressGestureRecognizerStateChanged:)];
    pahGestureRecognizer.delegate = self;
    pahGestureRecognizer.minimumPressDuration = 0.5;
    [self.viewB addGestureRecognizer:pahGestureRecognizer];

    [dtapGestureRecognize release];
    [tapGestureRecognize release];
    [pahGestureRecognizer release];
}

#pragma mark -
#pragma mark Button actions

- (IBAction)buttonTouchUpInside:(id)sender {
    NSLog(@"%s, %@", __FUNCTION__, sender);
}

#pragma mark -
#pragma mark Gesture recognizer actions


- (void)singleTapGestureRecognizer:(UIGestureRecognizer *)gestureRecognizer {
    NSLog(@"%s", __FUNCTION__);
}

- (void)doubleTapGestureRecognizer:(UIGestureRecognizer *)gestureRecognizer {
    NSLog(@"%s", __FUNCTION__);
}

- (void)longPressGestureRecognizerStateChanged:(UIGestureRecognizer *)gestureRecognizer {

    switch (gestureRecognizer.state) {

        case UIGestureRecognizerStateEnded: {
            NSLog(@"%s", __FUNCTION__);

            break;
        }
        default:
            break;
    }
}

在“shouldReceiveTouch”方法中，您应该添加一个条件，如果触摸在按钮中，该条件将返回NO

这是来自苹果的例子

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch {

    // Disallow recognition of tap gestures in the segmented control.
    if ((touch.view == yourButton)) {//change it to your condition
        return NO;
    }
    return YES;
}

希望能有所帮助

编辑

正如Daniel指出的，您必须遵守

UIgestureRecognitizerDelegate

，它才能工作

---

沙尼

我也有同样的问题，然后我试着用

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch{

    if ([touch.view isKindOfClass:[UIButton class]]) {      //change it to your condition
        return NO;
    }
    return YES;
}

---

它现在工作得很好………

一般来说，我们使用下面的委托方法来避免各种uicontrol中的触摸：

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch {
    if (([touch.view isKindOfClass:[UIControl class]])) {
         return NO;
    }
    return YES;
}

---

注意：不要执行此检查（检查recognizer.view类类型）GestureRecognitizer应该开始，它不会工作。

我认为最好的解决方案是使用下面的代码片段：

-(BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch {
    CGPoint touchLocation = [touch locationInView:self.view];
    return !CGRectContainsPoint(self.menuButton.frame, touchLocation);
}

---

以下是Swift版本：

func gestureRecognizer(gestureRecognizer: UIGestureRecognizer, shouldReceiveTouch touch: UITouch) -> Bool {
    if (touch.view!.isKindOfClass(UIButton)) {
        return false
    }
    return true
}

别忘了：

使您的类符合

UIgestureRecognitizerDelegate

将tapper对象委托给self（例如：

tapper.delegate=self

）

---

这是一个Swift 3.0版本：

extension UIViewController: UIGestureRecognizerDelegate {

public func gestureRecognizer(_ gestureRecognizer: UIGestureRecognizer, shouldReceive touch: UITouch) -> Bool {
    if touch.view is UIButton {
        return false
    }
    return true
}

别忘了：

---

将您的tapper对象委托给self（例如：tapper.delegate=self）

啊！！！是的，我忘记了这个-手势识别器：shouldReceiveTouch:方法。谢谢你给我指明了正确的方向。虽然这解决了我的问题，但我仍然不知道为什么响应者层次结构在这种情况下不起作用。它可能应该这样做，但苹果没有处理它。UIgestureRecognitor的行为被清楚地描述为与“正常”响应程序链分离。这是Apple的一个设计决定。记住遵照UigesturrErgOngIZError协议并将uigesturreCngnisher的委托设置为该对象。为了更广泛的使用，请考虑Ramesh或FrigBoT的测试子句的一些变体。例如，在我的例子中，我以以下行结束：

如果（[touch.view isKindOfClass:[UIControl类]]| |[[touch.view superview]isKindOfClass:[UITableViewCell类]]）{

…注意tableview单元格被“触摸”在他们的contentView中，它是一个私有类的成员，因此我们在这里检查superview的类。谢谢你的回答！在我的情况下，我遇到了相同的问题，但直到我在实际设备中进行测试后才发现它。在模拟器中运行应用程序而不使用UIGestureDelegate，如回答中所示，效果与预期一样虽然不正确。我只错过了

myGestureRecognizer.delegate=self；

最简单的方法是将cancelsTouchesInView=false