我想从MapKit for iPhone中的坐标值中获取位置名称

我想从坐标值中获取位置名称。这是代码

- (void)viewWillAppear:(BOOL)animated {  
    CLLocationCoordinate2D zoomLocation;
    zoomLocation.latitude = 39.281516;
    zoomLocation.longitude= -76.580806;
    MKCoordinateRegion viewRegion = MKCoordinateRegionMakeWithDistance(zoomLocation, 0.5*METERS_PER_MILE, 0.5*METERS_PER_MILE);
    MKCoordinateRegion adjustedRegion = [_mapView regionThatFits:viewRegion];                
    [_mapView setRegion:adjustedRegion animated:YES];      
}

---

所以，从那个纬度和经度，我想知道那个位置的名称。

在iOS 5.0和更高版本中，您可以使用核心位置框架的

CLGeocoder

，对于低于5.0的iOS，可以使用Map Kit框架的

MKReverseGeocoder

。祝你好运

使用这种方法

CLGeocoder *geocoder = [[CLGeocoder alloc] init]; 

[geocoder reverseGeocodeLocation: zoomLocation completionHandler:^(NSArray* placemarks, NSError* error){
}
 ];

---

以下代码应适用于ios5及以上版本

 CLGeocoder *ceo = [[CLGeocoder alloc]init];
 CLLocation *loc = [[CLLocation alloc]initWithLatitude:32.00 longitude:21.322]; //insert your coordinates

[ceo reverseGeocodeLocation:loc
          completionHandler:^(NSArray *placemarks, NSError *error) {
              CLPlacemark *placemark = [placemarks objectAtIndex:0];
              if (placemark) {


                  NSLog(@"placemark %@",placemark);
                  //String to hold address
                  NSString *locatedAt = [[placemark.addressDictionary valueForKey:@"FormattedAddressLines"] componentsJoinedByString:@", "];
                  NSLog(@"addressDictionary %@", placemark.addressDictionary);

                  NSLog(@"placemark %@",placemark.region);
                  NSLog(@"placemark %@",placemark.country);  // Give Country Name
                  NSLog(@"placemark %@",placemark.locality); // Extract the city name
                  NSLog(@"location %@",placemark.name);
                  NSLog(@"location %@",placemark.ocean);
                  NSLog(@"location %@",placemark.postalCode);
                  NSLog(@"location %@",placemark.subLocality);

                  NSLog(@"location %@",placemark.location);
                  //Print the location to console
                  NSLog(@"I am currently at %@",locatedAt);
              }
              else {
                  NSLog(@"Could not locate");
              }
          }
 ];

---

这里是从当前位置获取地址字符串的块

in .h file

typedef void(^addressCompletionBlock)(NSString *);

-(void)getAddressFromLocation:(CLLocation *)location complationBlock:(addressCompletionBlock)completionBlock;

in .m file
#pragma mark - Get Address
-(void)getAddressFromLocation:(CLLocation *)location complationBlock:(addressCompletionBlock)completionBlock
{
    //Example URL
    //NSString *urlString = @"http://maps.googleapis.com/maps/api/geocode/json?latlng=23.033915,72.524267&sensor=true_or_false";

    NSString *urlString = [NSString stringWithFormat:@"http://maps.googleapis.com/maps/api/geocode/json?latlng=%f,%f&sensor=true_or_false",location.coordinate.latitude, location.coordinate.longitude];

    NSError* error;
    NSString *locationString = [NSString stringWithContentsOfURL:[NSURL URLWithString:urlString] encoding:NSASCIIStringEncoding error:&error];
    NSArray *jsonObject = [NSJSONSerialization JSONObjectWithData:[locationString dataUsingEncoding:NSUTF8StringEncoding]
                                                          options:0 error:NULL];

    NSString *strFormatedAddress = [[[jsonObject valueForKey:@"results"] objectAtIndex:0] valueForKey:@"formatted_address"];
    completionBlock(strFormatedAddress);
}

CLLocation* currentLocation = [[CLLocation alloc] initWithLatitude:[SharedObj.current_Lat floatValue] longitude:[SharedObj.current_Long floatValue]];

    [self getAddressFromLocation:currentLocation complationBlock:^(NSString * address) {
        if(address) {
            NSLog(@"Address:: %@",address);
        }
    }];

和调用函数

in .h file

typedef void(^addressCompletionBlock)(NSString *);

-(void)getAddressFromLocation:(CLLocation *)location complationBlock:(addressCompletionBlock)completionBlock;

in .m file
#pragma mark - Get Address
-(void)getAddressFromLocation:(CLLocation *)location complationBlock:(addressCompletionBlock)completionBlock
{
    //Example URL
    //NSString *urlString = @"http://maps.googleapis.com/maps/api/geocode/json?latlng=23.033915,72.524267&sensor=true_or_false";

    NSString *urlString = [NSString stringWithFormat:@"http://maps.googleapis.com/maps/api/geocode/json?latlng=%f,%f&sensor=true_or_false",location.coordinate.latitude, location.coordinate.longitude];

    NSError* error;
    NSString *locationString = [NSString stringWithContentsOfURL:[NSURL URLWithString:urlString] encoding:NSASCIIStringEncoding error:&error];
    NSArray *jsonObject = [NSJSONSerialization JSONObjectWithData:[locationString dataUsingEncoding:NSUTF8StringEncoding]
                                                          options:0 error:NULL];

    NSString *strFormatedAddress = [[[jsonObject valueForKey:@"results"] objectAtIndex:0] valueForKey:@"formatted_address"];
    completionBlock(strFormatedAddress);
}

CLLocation* currentLocation = [[CLLocation alloc] initWithLatitude:[SharedObj.current_Lat floatValue] longitude:[SharedObj.current_Long floatValue]];

    [self getAddressFromLocation:currentLocation complationBlock:^(NSString * address) {
        if(address) {
            NSLog(@"Address:: %@",address);
        }
    }];

---

朋友们好，谢谢你们的回答，我很感激，但我得到了这个问题的解决方案，我无法发布答案，因为我没有超过10个的声誉。根据StackOverflow规则，我会在8小时后发布。在通过LAt&Long之后，我刚刚使用GoogleMapAPI获取位置字符串。这是一个很好的答案，尽管它使用GoogleMaps。。。我更喜欢用标准的iOS方式来获取位置。现在这个API不起作用。更多信息请访问这个URL。我认为，这应该是可以接受的答案。谢谢没有if块，else部分怎么能执行？@AppleDelegate先生在我的例子中，reversegeocodleocaiton块未执行您的CLGeocoder实例可能为零。